probabiilty..

[anjaneiya]

A man chooses an outfit from 3 different shirts, 2 different pairs of shoes, and 3 different pants. If he randomly selects 1 shirt, 1 pair of shoes, and 1 pair of pants each morning for 3 days, what is the probability that he wears the same pair of shoes each day, but that no other piece of clothing is repeated?

pl explain your approach...thanks...

OA_ [spoiler](1/3)^4[/spoiler]

[GMATGuruNY]

A man chooses an outfit from 3 different shirts, 2 different pairs of shoes, and 3 different pants. If he randomly selects 1 shirt, 1 pair of shoes, and 1 pair of pants each morning for 3 days, what is the probability that he wears the same pair of shoes each day, but that no other piece of clothing is repeated?

pl explain your approach...thanks...

OA_ [spoiler](1/3)^4[/spoiler]

The first day is immaterial; the man can wear whatever he wants. We're concerned only with what the man chooses to wear the second and third days. Here are the outcomes we need:

Second day: different shirt, different pair of pants, same pair of shoes
Third day: different shirt from those worn on days 1 and 2, different pair of pants from those worn on days 1 and 2, same pair of shoes

Let's determine each probability separately:

Probability of choosing a different shirt on the second day: 2/3 (because he has 3 shirts total, and he can't wear the same shirt worn the first day, leaving him 2 good choices)

Probability of choosing a different pair of pants on the second day: 2/3 (because he has 3 pairs total, and he can't wear the same pair worn the first day, leaving him 2 good choices)

Probability of choosing the same pair of shoes: 1/2 (because he has 2 pairs total, and he has to wear the same pair worn the first day, leaving him 1 good choice)

Probability of choosing a different shirt on the third day: 1/3 (because he has 3 shirts total, and he can't wear either of the 2 shirts worn the first 2 days, leaving him only 1 good choice)

Probability of choosing a different pair of pants on the third day: 1/3 (because he has 3 pairs total, and he can't wear either of the 2 pairs worn the first 2 days, leaving him only 1 good choice)

Probability of choosing the same pair of shoes: 1/2 (because he has 2 pairs total, and he has to wear the same pair worn the first day and second days, leaving him 1 good choice)

We need all of these events to happen together in order to get a good outcome. To determine the probability that multiple events will happen together, remember this rule:

Probability of (A and B) = Probability(A) * Probability (B)

We multiply the probabilities because the more things we want to happen together, the smaller the probability, and when we multiply fractions, the result keeps getting smaller.

So let's take the probabilities that we determined above and multiply:

2/3 * 2/3 * 1/2 * 1/3 * 1/3 * 1/2 = (1/3)^4

[anjaneiya]

soooo...easy.

thanks guru.