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Selecting participants

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Selecting participants

by ronsom » Fri May 21, 2010 1:57 am
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by liferocks » Fri May 21, 2010 2:01 am
18C4 ways which is equal to (18*17*16*15)/(4*3*2*1)=3060

Ans option E
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by Patrick_GMATFix » Fri May 21, 2010 3:27 am
This is QID 1406.

Because the order is irrelevant, it's a straightforward combination: how many ways can 18 items be put in groups of 4? 18!/4!14!

-Patrick
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