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Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and 602. In terms of q, what is the value of 1/p + 1/q ?
(A) 1/(600q)
(B) 1/(359,999q)
(C) 1,200/q
(D) 360,000/q
(E) 359,999q
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Veritas Prep Challenge Question
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Ashley@VeritasPrep
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Ashley Newman-Owens
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Post helpful? Mosey your cursor on over to that Thank button and click, please! I will bake you an imaginary cake.
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Post helpful? Mosey your cursor on over to that Thank button and click, please! I will bake you an imaginary cake.
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and 602. In terms of q, what is the value of 1/p + 1/q ?
(A) 1/(600q)
(B) 1/(359,999q)
(C) 1,200/q
(D) 360,000/q
(E) 359,999q
Answer: D 360,000/q
q=p*599*601= 359999p
therefore, p=q/359,999
1/p + 1/q = 1/(q/359,999) + 1/q
= 359,999/q +1/q = 360,000/q
(A) 1/(600q)
(B) 1/(359,999q)
(C) 1,200/q
(D) 360,000/q
(E) 359,999q
Answer: D 360,000/q
q=p*599*601= 359999p
therefore, p=q/359,999
1/p + 1/q = 1/(q/359,999) + 1/q
= 359,999/q +1/q = 360,000/q
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krishnasty
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p = 501*503*..........597
q = 501*503*..........597*599*601
hence,
q = p * 599*601
p = q/(599*601)
1/p + 1/p = (599*601)/q + 1/q =
360000/q
Ans: D
q = 501*503*..........597*599*601
hence,
q = p * 599*601
p = q/(599*601)
1/p + 1/p = (599*601)/q + 1/q =
360000/q
Ans: D
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nav!n
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p= 501x503...x597
q=501x503....x599x601
p =q/(599x601)
1/p +1/q = [(599x601)+1]/q = 360000/q
D is correct.
q=501x503....x599x601
p =q/(599x601)
1/p +1/q = [(599x601)+1]/q = 360000/q
D is correct.
Dear life , When I said "Can my day get any worse" It was a rhetorical question not a challenge!
Answer: (D)
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and 602. In terms of q, what is the value of 1/p + 1/q ?
(A) 1/(600q)
(B) 1/(359,999q)
(C) 1,200/q
(D) 360,000/q
(E) 359,999q
Solution:
p=501*502*503*..... ...*597
q=501*502*503*..... ...*597*599*601
--> q=p*599*601
--> p=q/(599*601)
(1/p) + (1/q)= (599*601)/q + 1/q
= (359999 + 1)/q
= 360,000/q -- Answer(D)
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and 602. In terms of q, what is the value of 1/p + 1/q ?
(A) 1/(600q)
(B) 1/(359,999q)
(C) 1,200/q
(D) 360,000/q
(E) 359,999q
Solution:
p=501*502*503*..... ...*597
q=501*502*503*..... ...*597*599*601
--> q=p*599*601
--> p=q/(599*601)
(1/p) + (1/q)= (599*601)/q + 1/q
= (359999 + 1)/q
= 360,000/q -- Answer(D)
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eubschoolasp
- Junior | Next Rank: 30 Posts
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Solution:
Since, p=501*503*505*....*597 (product of all odd integers between 500 and 598)
and q=501*503*505*.....*597*599*601 (product of all odd integers between 500 and 602),
We may re-write q= p*599*601
or,q= p*359999
or,p= q/359999
Hence, 1/p + 1/q= 359999/q + 1/q
= (359999+1)/q
= 360,000/q
Choose (D).
Since, p=501*503*505*....*597 (product of all odd integers between 500 and 598)
and q=501*503*505*.....*597*599*601 (product of all odd integers between 500 and 602),
We may re-write q= p*599*601
or,q= p*359999
or,p= q/359999
Hence, 1/p + 1/q= 359999/q + 1/q
= (359999+1)/q
= 360,000/q
Choose (D).
