Pls refer the image below for the question.
Units Digit
This topic has expert replies
- outreach
- Legendary Member
- Posts: 748
- Joined: Sun Jan 31, 2010 7:54 am
- Thanked: 46 times
- Followed by:3 members
(3*2^3)^(2x+1)*(3*11)^(x+1)*(17)^(x+2)*(3)^4x
(3)^(2x+1+x+1+4x)*2^(6x+3)*(11)^(x+1)*(17)^(x+2)
(3)^(7x+2)*2^(6x+3)*(11)^(x+1)*(17)^(x+2)
2,3,7 has cyclicity of 4
if x=1
3^9*2^9*11^2*17*3=> remainder=3*2*1*3=18
if x=2
3^16*2^15*11^3*17*4=> remainder=1*8*1*1=8
similarly for other x value we will get unit digit as 8
D
(3)^(2x+1+x+1+4x)*2^(6x+3)*(11)^(x+1)*(17)^(x+2)
(3)^(7x+2)*2^(6x+3)*(11)^(x+1)*(17)^(x+2)
2,3,7 has cyclicity of 4
if x=1
3^9*2^9*11^2*17*3=> remainder=3*2*1*3=18
if x=2
3^16*2^15*11^3*17*4=> remainder=1*8*1*1=8
similarly for other x value we will get unit digit as 8
D
-------------------------------------
--------------------------------------
General blog
https://amarnaik.wordpress.com
MBA blog
https://amarrnaik.blocked/
--------------------------------------
General blog
https://amarnaik.wordpress.com
MBA blog
https://amarrnaik.blocked/
-
- Senior | Next Rank: 100 Posts
- Posts: 57
- Joined: Sun Jul 06, 2008 10:52 am
- Thanked: 1 times
- GMAT Score:640
Hi All,
Since we have an equation given,
can we substitute a value for X.Let x=0
then the unit digit values would be **4 x **3 X **9 X 1 (as 9^0=1)
Then the answer is ****8.
Thanks
karthik
Since we have an equation given,
can we substitute a value for X.Let x=0
then the unit digit values would be **4 x **3 X **9 X 1 (as 9^0=1)
Then the answer is ****8.
Thanks
karthik
-
- Senior | Next Rank: 100 Posts
- Posts: 77
- Joined: Fri Jan 08, 2010 7:55 am
- Thanked: 2 times
- GMAT Score:700
The plug-in method is pretty fast in such problems.iikarthik wrote:Hi All,
Since we have an equation given,
can we substitute a value for X.Let x=0
then the unit digit values would be **4 x **3 X **9 X 1 (as 9^0=1)
Then the answer is ****8.
Thanks
karthik
However, we can not use zero as X since X has to be a positive integer.
-
- Legendary Member
- Posts: 2326
- Joined: Mon Jul 28, 2008 3:54 am
- Thanked: 173 times
- Followed by:2 members
- GMAT Score:710
My method is to plug in a integer for X
Let X = 1
Eqn becomes : 24^3 .33^2.17^3.9^2
:4*9*3*1
: __8
Pick D
Let X = 1
Eqn becomes : 24^3 .33^2.17^3.9^2
:4*9*3*1
: __8
Pick D
-
- Senior | Next Rank: 100 Posts
- Posts: 57
- Joined: Sun Jul 06, 2008 10:52 am
- Thanked: 1 times
- GMAT Score:640
pharmxanthan wrote:The plug-in method is pretty fast in such problems.iikarthik wrote:Hi All,
Since we have an equation given,
can we substitute a value for X.Let x=0
then the unit digit values would be **4 x **3 X **9 X 1 (as 9^0=1)
Then the answer is ****8.
Thanks
karthik
However, we can not use zero as X since X has to be a positive integer.
Hi
Thanks for correcting my mistake
- sumanr84
- Legendary Member
- Posts: 758
- Joined: Sat Aug 29, 2009 9:32 pm
- Location: Bangalore,India
- Thanked: 67 times
- Followed by:2 members
I too did this prob in the same way. I think this is the best approach to save time.gmatmachoman wrote:My method is to plug in a integer for X
Let X = 1
Eqn becomes : 24^3 .33^2.17^3.9^2
:4*9*3*1
: __8
Pick D