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The perimeter of a rectangular yard is completely

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The perimeter of a rectangular yard is completely Post Sun May 25, 2014 2:35 pm
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    The perimeter of a rectangular yard is completely surrounded by a fence that measures 40 meters. What is the length of the yard if the area of the yard is 64 meters squared?


    A)8
    B)10
    C)12
    D)14
    E)16


    OA E

    Source MGMT CAT

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    Post Sun May 25, 2014 3:03 pm
    canbtg wrote:
    The perimeter of a rectangular yard is completely surrounded by a fence that measures 40 meters. What is the length of the yard if the area of the yard is 64 meters squared?

    A)8
    B)10
    C)12
    D)14
    E)16

    Let L = the length of the rectangle
    Let W = the width of the rectangle

    The perimeter is 40 meters.
    So, L + L + W + W = 40
    Simplify: 2L + 2W = 40
    Divide both sides by 2 to get: L + W = 20

    The area is 64 square meters.
    So, LW = 64

    We now have two equations.

    First, if L + W = 20, then W = 20 - L

    Now take LW = 64 and replace W with (20 - L) to get: L(20 - L) = 64
    Expand to get: 20L - L² = 64
    Rearrange to get: L² - 20L + 64 = 0
    Factor: (L - 4)(L - 16) = 0
    So, L = 4 or L = 16

    So, it LOOKS like we have two different solutions. However, they are actually the SAME solution.

    If L = 4, then W = 16
    If L = 16, then W = 4

    So, the dimensions of the rectangle are 4 X 16. So, we can say that the length is EITHER 4 or 16.

    Since only 16 appears among the answer choices, the correct answer must be E

    Cheers,
    Brent

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    Post Sun May 25, 2014 6:47 pm
    Hi canbtg,

    This question can also be solved by TESTing THE ANSWERS.

    We're told that the Perimeter of the yard is 40 and its Area is 64. We're asked for the Length of the yard.

    Perimeter = 2L + 2W = 40
    Area = (L)(W)

    Since the answer choices are all integers, my suspicion is that both the length and width of the yard are integers. Which provides an interesting opportunity, since 64 can be "broken down" into just a few options:

    1x64
    2x32
    4x16
    8x8

    From the given answers, my guess would be either A or E would be the answer. I'll test those options to see if either fits the info in the prompt.

    If the yard was 8x8, then the perimeter would be 32, which is NOT a match (the perimeter is supposed to be 40).
    If the yard was 4x16, then the perimeter would be 40, which IS a match.

    So, either 4 or 16 could be the solution.

    Final Answer: E

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    Post Mon May 26, 2014 8:25 am
    2*(L+B) = 40

    L+B = 20

    LB = 64

    Possible combination is 16 & 4

    16 is present in answer choices

    so {E}

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    Post Sat Dec 31, 2016 2:21 am
    Let us solve this problem via back solving method.


    Let’s start with C, the middle value. If the length of the yard is 12 and the perimeter is 40, the width would be 8 (perimeter - 2l = 2w). With a length of 12 and a width of 8, the area would be 96. This is too big of an area.

    It may not be intuitive whether we need the length to be longer or shorter, based on the above outcome. Consider the following geometric principle: for a fixed perimeter, the maximum area will be achieved when the values for the length and width are closest to one another. A (10 X 10) rectangle has a much bigger area than an 18 X 2 rectangle. Put differently, when dealing with a fixed perimeter, the greater the disparity between the length and the width, the smaller the area.

    Since we need the area to be smaller than 96, it makes sense to choose a longer length so that the disparity between the length and width will be greater.

    When we get to answer choice E, we see that a length of 16 gives us a width of 4 (perimeter - 2l = 2w). Now the area is in fact 16 X 4 = 64.

    The correct answer is E

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