The three solutions of the equation f (x) = 0 are -2, 0, and 3. Therefore, the three solutions of the equation f (x - 2) = 0 are
(A) - 4, -2, and 1
(B) -2, 0 and 3
(C) 4, 2, and 5
(D) 0, 2 and 5
(E) 2, 4, and 7
solutions of the equation
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- sanju09
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three solutions of the equation f (x) = 0 are -2, 0, and 3 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x
so f(x-2)=(x)(x-2)(x-5)P(X-2)
So three solutions of f(x-2) is 0, 2 and 5
Ans option D
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x
so f(x-2)=(x)(x-2)(x-5)P(X-2)
So three solutions of f(x-2) is 0, 2 and 5
Ans option D
Last edited by liferocks on Wed May 19, 2010 4:54 am, edited 1 time in total.
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this is called hangoverliferocks wrote:three solutions of the equation f (x) = 0 are - 4, 8, and 11 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x
so f(x-2)=(x)(x-2)(x-5)P(X-2)
So three solutions of f(x-2) is 0, 2 and 5
Ans option D
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
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hmm...copy paste from ur other question solution..editedsanju09 wrote:this is called hangoverliferocks wrote:three solutions of the equation f (x) = 0 are - 4, 8, and 11 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x
so f(x-2)=(x)(x-2)(x-5)P(X-2)
So three solutions of f(x-2) is 0, 2 and 5
Ans option D
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