If x and y are positive integers and x/y has a remainder of 5 , what is the smallest possible value of xy?
Here is understand that since the remainder is 5 , the smallest possible integer (y) should be 6 . I am not able to proceed further . This problem is taken from MGMAT.
The OA is 30
Smallest possible value
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You are in the right track.Deepthi Subbu wrote:If x and y are positive integers and x/y has a remainder of 5 , what is the smallest possible value of xy?
Here is understand that since the remainder is 5 , the smallest possible integer (y) should be 6 . I am not able to proceed further . This problem is taken from MGMAT.
The OA is 30
To minimize xy, we have to minimize both of x and y.
Minimum value of y is 6 because if y < 6 we'll never get a remainder of 5.
Now the question is what is the minimum possible value of x for which x/6 has a remainder of 5. And we are looking at the answer! Minimum possible value of x is 5!
Thus, minimum possible value of xy is 5*6 = 30.
Rahul Lakhani
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On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)