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simple fraction q, but i got it wrong

This topic has 5 member replies
tj123 Senior | Next Rank: 100 Posts Default Avatar
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Posted:
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simple fraction q, but i got it wrong

Post Mon Jun 22, 2009 10:27 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resoltion and still have it pass?

    A) 19
    B) 17
    c) 16
    D) 14
    e) 13

    OA e

    I chose B because 2/3 of 40 is 26, which means 14 is the max that can vote against a resolution and still have it pass. why is my methodology wrong

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    pops Master | Next Rank: 500 Posts Default Avatar
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    Post Mon Jun 22, 2009 10:38 pm
    No,
    If 14 votes against the resolution then it wont pass since:
    26/40 = 0.65 and required is 2/3 = 0.66

    BlindVision Master | Next Rank: 500 Posts
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    Post Tue Jun 23, 2009 12:54 am
    tj123 wrote:
    At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resoltion and still have it pass?

    A) 19
    B) 17
    c) 16
    D) 14
    e) 13

    OA e

    I chose B because 2/3 of 40 is 26, which means 14 is the max that can vote against a resolution and still have it pass. why is my methodology wrong
    If 2/3 = for resolution to pass then 1/3 = resolution to not pass.

    The question is asking what is the most votes of "resolution to not pass" and "still have it pass"

    40(1/3) = 13.3, rounded to 13

    Go E

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    rah_pandey Master | Next Rank: 500 Posts Default Avatar
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    Post Tue Jun 23, 2009 3:45 am
    I think the confusion is with decimals as 80/3 is not integer. So the thumb rule for passing a resolution
    an integer no of votes should be in favour
    if by solving we get a fraction than it needs to rounded off to next HIGHER integer even if fraction part is less than 0.5

    ssmiles08 Master | Next Rank: 500 Posts
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    Post Tue Jun 23, 2009 5:13 am
    Alternatively, you can find the minimum to pass to find the maximum that can vote no.

    for the bill to pass at least 2/3 ~ 2/3(40) = 26.667 ~ 27 (b/c 26 votes will still cause a bill to fail)

    so the rest of the votes can be no 40-27 = 13. (E)

    tj123 Senior | Next Rank: 100 Posts Default Avatar
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    Post Tue Jun 23, 2009 9:49 am
    thanks i should have rounded up.
    that was my mistake
    thanks

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