If |X|<3, is X<3?

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If |X|<3, is X<3?

by pdshah » Sun Feb 12, 2012 10:22 am
My interpretation of this is X could be either smaller than 3 or greater than -3 and hence INSUFFICIENT:
X<3
or -X<3 => X>-3
Since the keyword here is OR, not AND, I thought this is insufficient. X>-3 means X could have any value smaller or greater than 3.

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by Mike@Magoosh » Sun Feb 12, 2012 3:41 pm
Hi, there. I'm happy to help with this. :)

First of all, this is odd, because it's not a complete DS question. I assume it comes from something like:

Prompt: is x<3

one of the statements: |x|<3

Well, think about |x|<3. That means x is has a distance less than 3 from the origin. The solution to |x|<3 is the compound inequality -3 < x < 3. The value of x must be between -3 and 3. Of course, if x is anywhere in that range, it's less than 3, so this is sufficient.

The problem with pdshah's solution is: the proper word in the solution to that particular inequality is "and", not "or."

If |x|<3, then x<3 and -x<3 ==> x>-3. That gives us a narrow range on the number line that's a solution.

If the word were "or", and the solution x<3 or x>-3, that's the entire number line. Every real number is either less than 3 or greater than -3. Clearly, this inequality does not have a solution of all real numbers. That's why "or" is wrong.

Does that make sense? Please let me know if you have any further questions.

Mike :)
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https://gmat.magoosh.com/

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by pdshah » Sun Feb 12, 2012 8:52 pm
Mike
Your response makes sense. As soon as you mentioned the number line, the lightbulb turned on.
Thanks

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by [email protected] » Sat Feb 18, 2012 8:16 am
Very important and helpful explanation given.... Thank You!!!
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