Search found 447 matches
- by Mathsbuddy
Fri Dec 19, 2014 2:54 am- Forum: Problem Solving
- Topic: Help me solve this GMAT Quant Question (GMATPrep) #5
- Replies: 5
- Views: 2424
2-digit common multiples of 6 and 10 are:
30, 60 and 90
Therefore the answer is 3 (D).
(The actual value of the remainder is redundant information)
- by Mathsbuddy
Fri Dec 19, 2014 2:48 am- Forum: Problem Solving
- Topic: how to solve efficiently
- Replies: 3
- Views: 1495
BDC and AEC are similar triangles.
AE is 40 and BD is 5, so the larger triangle is 8 times the area of the smaller one.
The area of BDC is 5 x 10/2 = 25
Therefore AEC has area 25 x 8 = 200
200-25 = 175
Answer A
- by Mathsbuddy
Fri Dec 19, 2014 2:40 am- Forum: Problem Solving
- Topic: In the diagram above, BD = 5, CD = 10, and AE = 40. What is
- Replies: 6
- Views: 2921
"Whole Factors" of 60! that produce multiples of 10 are: 60, 50, 40, 30, 20, 10 and 2 x 55, 4 x 45, 6 x 35, 8 x 25, 12 x 15, 14 x 5 This totals 12 in number Surely any other factors are intrinsic to these? Or indeed, even numbers greater than this cannot be counted as all the multiples of ...
- by Mathsbuddy
Fri Dec 19, 2014 2:36 am- Forum: Problem Solving
- Topic: Trailiiiiiing zer0s
- Replies: 21
- Views: 12020
Remember rate questions use reciprocals:
A's rate = 1/6
B's rate = 1/12
Joint rate = 1/6 + 1/12 = 1/4
2 days at 1/4 = 2 x 1/4 = 1/2 -> job is half complete
A's new rate = 0.75 x 1/6 = 1/8 to do the other half of the job
so A will take 8/2 = 4 days
- by Mathsbuddy
Tue Dec 16, 2014 8:12 am- Forum: Problem Solving
- Topic: Time taken by A to complete a
- Replies: 7
- Views: 2241
Comparing ratios is very simple -
P:Q:difference
1:4:3
2:8:6
2 revolutions takes 2/10 minutes = 12 seconds
- by Mathsbuddy
Tue Dec 16, 2014 8:03 am- Forum: Problem Solving
- Topic: Work Problem
- Replies: 9
- Views: 2403
Alternatively, we can see that a SUBTRACTION is required, so we can use this clue to bring us closer to the answer on the right hand side of the equation:
3 x 2^13 = (4-1) x 2^13 = 4 x 2^13 - 2^13 = 2^15 - 2^13 = 2^n - 2^(n-2)
So n = 15
- by Mathsbuddy
Tue Dec 16, 2014 7:55 am- Forum: Problem Solving
- Topic: Help me solve this GMAT Quant Question (GMATPrep) #2
- Replies: 3
- Views: 1941
Surely it is irrelevant that there are 3 pads each time?
Then it leaves pads of same/different colour or same/different size.
Surely this means that all combinations are valid?
Number of combinations = 2^4 = 16
Is this logic flawed?
- by Mathsbuddy
Tue Dec 16, 2014 5:39 am- Forum: Problem Solving
- Topic: Help me solve this GMAT Quant Question (GMATPrep) #3
- Replies: 9
- Views: 4191
Upon visualising the given coordinates it is easy (and fast) to realise that the triangle is symmetrical about the line y = -x. Therefore, if the x co-ordinate of the third vertx is 6, then the y co-ordinate must be -6.
No need for any trig or Pythagoras.
- by Mathsbuddy
Wed Dec 10, 2014 7:27 am- Forum: Problem Solving
- Topic: Points J (3, 1) and K (– 1, – 3) are two vertices of an
- Replies: 4
- Views: 2024
Two-thirds of the circumference = 24
So one third is 12
So the whole circumference, C = 36
Diameter, D = C/pi
pi = 3 (approx)
so D = 36/3 = 12 approx.
ANSWER C
- by Mathsbuddy
Wed Dec 10, 2014 7:22 am- Forum: Problem Solving
- Topic: diameter of triangle! please help
- Replies: 3
- Views: 2187
In the coordinate plane, a circle has center (2, -3) and passes through the point (5, 0). What is the area of the circle? The displacement between points (2,-3) and (5,0) is the radius of the circle. Change in x = 5 - 2 = 3 Change in y = 0 - -3 = 3 By Pythagoras: r^2 = 3^2 + 3^2 = 18 Area = pi x r^2...
- by Mathsbuddy
Wed Dec 03, 2014 7:18 am- Forum: Problem Solving
- Topic: Geometry
- Replies: 4
- Views: 1699
p1(blue) = 5/12
p2(green) = 4/11
p3(yellow) = 3/10
P(all 3) = 5/12 x 4/11 x 3/10 = 60/1320 = 1/22
REMEMBER: we MULTIPLY probabilities for AND logic
- by Mathsbuddy
Thu Nov 27, 2014 11:53 am- Forum: Problem Solving
- Topic: Probability
- Replies: 36
- Views: 15035
Here's a another way of working backwards from the answers. Answers changed to reflect manufacturing just w widgets: A. x = 2, y = 0: 1/2 + 1/0 = UNDEFINED B. x = 3, y = 1: 1/3 + 1/1 = 4/3 in 1 day, so 4 in 3 days C. x = 4, y = 2: 1/4 + 1/2 = 3/4 in 1 day, so 9/4 in 3 days D. x = 5, y = 3: 1/5 + 1/...
- by Mathsbuddy
Thu Nov 27, 2014 11:45 am- Forum: Problem Solving
- Topic: Difficulty Level
- Replies: 12
- Views: 3347
Here's a another way of working backwards from the answers. Answers changed to reflect manufacturing just w widgets: A. x = 2, y = 0: 1/2 + 1/0 = UNDEFINED B. x = 3, y = 1: 1/3 + 1/1 = 4/3 in 1 day, so 4 in 3 days C. x = 4, y = 2: 1/4 + 1/2 = 3/4 in 1 day, so 9/4 in 3 days D. x = 5, y = 3: 1/5 + 1/3...
- by Mathsbuddy
Thu Nov 27, 2014 11:35 am- Forum: Problem Solving
- Topic: Difficulty Level
- Replies: 12
- Views: 3347
So, 12(x -2) + 12x = 5x(x-2) Rearrange to make a quadratic: 5x^2 - 34x + 24 = 0 (5x-4)(x-6) = 0 x = 4 or 6 As X takes 2 days longer than Y, then x = 6, y = 4 to make w widgets Therefore, 2w widgets take X 12 days to make. The highlighted step should be x = 4/5 or 6 Well spotted... oops! Thanks for ...
- by Mathsbuddy
Thu Nov 27, 2014 11:23 am- Forum: Problem Solving
- Topic: Difficulty Level
- Replies: 12
- Views: 3347