Search found 21 matches
Ya I remember the Boxed ones... Solved it here recently but could not find the post :( [9] = 3*9 = 27 as 9 is odd we have to get 3m here [6] = 1/2 * 6 = 3 as 6 is even so we have to get 1/2 m here now [9]*[6] = 27 * 3 = 81 81 is exact value but what will be the boxed value? The [odd] = 3*odd = 81 W...
- by anhe123
Tue Oct 19, 2010 6:47 am- Forum: Problem Solving
- Topic: GMAT Prep
- Replies: 9
- Views: 1488
GMAT Prep
Has uploaded a picture so you can see the whole queston, think thisone is really hard.
Thnaks
André
- by anhe123
Tue Oct 19, 2010 6:30 am- Forum: Problem Solving
- Topic: GMAT Prep
- Replies: 9
- Views: 1488
h(100) = 2*4*6*...*100 take all of the 2 common then h(100) = (2*2*...50 times) * (1*2*3*...*50) = 2^50*(1*2*3*...*50). Hence, all integers up to 50 are factors of h(100). Now if h(100) + 1 is divided by any integers from 1 to 50 will have a remainder 1 as h(100) is divisible by all integers below ...
- by anhe123
Sat Oct 16, 2010 3:52 am- Forum: Problem Solving
- Topic: GMAT Prep - Functions
- Replies: 5
- Views: 1465
- by anhe123
Sat Oct 16, 2010 3:39 am- Forum: Problem Solving
- Topic: GMAT prep - two triangles areas
- Replies: 2
- Views: 1129
GMAT Prep - Functions
For every positive integer n, the function h(n) is defined to be the product of all the even integers from 2 to n, inclusive. If p is the smallest prime factor of h(100) + 1, then p is a) between 2 and 10 b) between 10 and 20 c) between 20 and 30 d) between 30 and 40 e) greater than 40 Answer: e I f...
- by anhe123
Sat Oct 16, 2010 3:30 am- Forum: Problem Solving
- Topic: GMAT Prep - Functions
- Replies: 5
- Views: 1465
kmittal82 wrote:First you need to expand each of the brackets:
(A*B) = (12*15) = 3 (3 is the greatest common factor of 12 and 15)
(A$B) = (12$15) = 60 (60 is the least common multiple of 12 and 15)
>(A*B) $ (A$B),
= 3 $ 60 = Least common multiple of 3 and 60 = 60
But what does the dollar sign ($) mean?
- by anhe123
Thu Sep 30, 2010 6:43 am- Forum: Problem Solving
- Topic: Defined functions
- Replies: 4
- Views: 1813
Defined functions
If A*B is the greatest common factor of A and B, A$B is defined as the least common multiple of A and B, and (A intersection B) is defined as equal to (A*B) $ (A$B), then what is the value of (12 intersection 15)? How would you solve this? Are there any tips you have for solvning defined functions?[...
- by anhe123
Thu Sep 30, 2010 6:27 am- Forum: Problem Solving
- Topic: Defined functions
- Replies: 4
- Views: 1813
I think it is the probability of getting P(3/5) + P(4/5) + P(5/5)
which would be 0.2^3 + 0.2^4 + 0.2^5
This is not a GMAT wuestion, but something I though could be a question and was not sure how to answer
- by anhe123
Sat Sep 11, 2010 1:05 pm- Forum: Problem Solving
- Topic: 5 questions, get 3 right
- Replies: 4
- Views: 1137
5 questions, get 3 right
If there are five questions I have to answer, there are 5 alternatives to each question, and I need to get 3 right.
What are the odds I get 3 out of 5 right?
Thanks!
- by anhe123
Sat Sep 11, 2010 6:16 am- Forum: Problem Solving
- Topic: 5 questions, get 3 right
- Replies: 4
- Views: 1137
- by anhe123
Thu Aug 26, 2010 5:29 am- Forum: Data Sufficiency
- Topic: Geometry
- Replies: 2
- Views: 1067
don't know where to begin or what the question is
This question I cannot answer: For every integer K from 1 to 10, inclusive, the K th term of a certain sequence is given by (-1)^( K +1) * (1/(2^ K )). If T is the sum of the first 10 terms in the sequence, then T is: a) Greater than 2 b) Between 1 and 2 c) Between 1/2 and 1 d) Between 1/4 and 1/2 e...
- by anhe123
Thu Aug 26, 2010 5:05 am- Forum: Problem Solving
- Topic: don't know where to begin or what the question is
- Replies: 3
- Views: 874
Hmm, here's how I approached it, but got stuck at the end 3^(x-1) = (3^x)/3 3^x - 3^(x-1) = 3^x - (3^x/3) = 3^5 Multiply both sides by 3 => 3^(x+1) - 3^x = 3^6 Now, 3^(x+1 ) = 3^x * 3 Factoring out 3^x 3^x(3 - 1) = 3^6 => 3^x = 3^6 x 0.5 This gives a non-integer value for x Could you please give th...
- by anhe123
Thu Aug 26, 2010 4:38 am- Forum: Problem Solving
- Topic: 3^x - 3^(x-1) = 3^5
- Replies: 8
- Views: 1377
3^x - 3^(x-1) = 3^5
How do you solve for X in this equation?
Do you have any sources where I can read more about it?
3^x - 3^(x-1) = 3^5
- by anhe123
Thu Aug 26, 2010 3:54 am- Forum: Problem Solving
- Topic: 3^x - 3^(x-1) = 3^5
- Replies: 8
- Views: 1377
- by anhe123
Wed Aug 25, 2010 8:48 am- Forum: Problem Solving
- Topic: Difficult Math Question #5
- Replies: 8
- Views: 8894
First of all. Congratulations on a great score!
It seems to me that you are well above the minimum requirements. So the rest is probably up to your personality and experience, I guess..
But on the other hand, if you are confident you can raise your Q:Score, then why not.
Good luck!
- by anhe123
Mon Aug 23, 2010 7:25 am- Forum: I just Beat The GMAT!
- Topic: Beat the GMAT, sort of, not really (720: Q44 / V45); Retake?
- Replies: 11
- Views: 3558