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two consecutive odd positive integers
Find two consecutive odd positive integers, sum of whose squares is 290.
(a) 19,17
(b) 23,27
(c) 11,-13
(d) 7,9
help me to solve it.......
- by aarati
Wed Aug 11, 2010 10:50 pm- Forum: Problem Solving
- Topic: two consecutive odd positive integers
- Replies: 2
- Views: 1218
selango wrote:C=k/R
4=K/R
C=k/(1/3*R)
C=3*k/R=3*4=12
thank u....but ,can you explain me a bit clear ....
- by aarati
Wed Aug 11, 2010 10:47 pm- Forum: Problem Solving
- Topic: Proportaions
- Replies: 3
- Views: 1055
thank you very much ...i understood your logic..now i can solve these type of problems... thank you very much your simple great....nithi_mystics wrote:Total time taken = 840/60 = 14 hours.
The train reached Chicago at 6 PM. So it should have started Newyork at 4 AM (Chicago time) ie., 5 AM NewYork time.
- by aarati
Wed Aug 11, 2010 10:35 pm- Forum: Problem Solving
- Topic: Problem Solving
- Replies: 3
- Views: 1189
If the answer is E then the question needs little modification, I am not sure though. Instead of the price of wheat decreasing at a rate "square root (2x)-x" it needs to be "square root(2)x-x". If considered the latter one the problem can be solved in the following way: 320 + 5x...
- by aarati
Wed Aug 11, 2010 10:27 pm- Forum: Problem Solving
- Topic: PS bushel price
- Replies: 10
- Views: 2305
Solution: nPr is n!/(n-r)! and nCr is n!/{r!*(n-r)!}. So nPr/nCr is r! which is 30240/252 = 120 = 5! So r is 5. We need not look for n because in all options there is only one choice where r is 5. Correct answer is (10,5). thank u ..... you said u must ignore n because in all options there is only ...
- by aarati
Wed Aug 11, 2010 10:23 pm- Forum: Problem Solving
- Topic: help me to solve this ps problem
- Replies: 3
- Views: 1490
9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of arranging one ball in each of the boxes is (a) 18720 (b)18270 (c)17280 (d)12780 help me to solve it...... No. of ways 5 balls can be placed in 6 boxes (except 3 small boxes) = 6P5 = 6!/(6-5)!...
- by aarati
Wed Aug 11, 2010 10:10 pm- Forum: Problem Solving
- Topic: Arrangement problem........
- Replies: 2
- Views: 1349
Hi, Unlikely to be GMAT level ... x - 3 = (2/(3+sqrt{7})) - 3 = (-7-3sqrt(7))/(3+sqrt(7)) Squaring the previous term will lead to 7. thank u very much... can u explain me in step by step procedure please.... In problems like these, you have to rationalize the denominator i.e. make it into an intege...
- by aarati
Wed Aug 11, 2010 10:03 pm- Forum: Problem Solving
- Topic: challenging ps for me......
- Replies: 7
- Views: 1458
- by aarati
Wed Aug 11, 2010 9:27 pm- Forum: Problem Solving
- Topic: Permutations and Combinations
- Replies: 8
- Views: 1837
Find the exponent of 3 in 100!. please help me to solve it............ Divide 100 by powers of 3 to get the exponent of 3 in 100! 100/3 = 33 100/9 = 11 100/27 = 3 100/81 = 1 Hence exponent of 3 = 33+11+3+1 = 48 Hope this helps!! thank u very much .......i understood how to solve it.......you are si...
- by aarati
Wed Aug 11, 2010 9:25 pm- Forum: Problem Solving
- Topic: how to solve these ps question
- Replies: 6
- Views: 1100
also got 36 at first give everybody 2 coins. and left with 13-2*6=7 coins with no any restrictions 7 coins can be distributed among 3 persons in 9!/(7!*2!)=36 ways *******||. or ***|*|*** or *****||** or..... total number of ways=36 thank you very much........ i understood logic.......i think formu...
- by aarati
Wed Aug 11, 2010 8:38 pm- Forum: Problem Solving
- Topic: how to solve this type of questions..............
- Replies: 8
- Views: 1522
4GMAT_Mumbai wrote:Hi,
Unlikely to be GMAT level ...
x - 3 = (2/(3+sqrt{7})) - 3
= (-7-3sqrt(7))/(3+sqrt(7))
Squaring the previous term will lead to 7.
thank u very much... can u explain me in step by step procedure please....
- by aarati
Tue Aug 10, 2010 11:52 pm- Forum: Problem Solving
- Topic: challenging ps for me......
- Replies: 7
- Views: 1458
Three workers A, B, and C are hired for 4 days. The daily wages of the three workers are as follows: A's first day wage is $4. Each day, his wage increases by 2 dollars. B's first day wage is $3. Each day, his wage increases by 2 dollars. C's first day wage is $1. Each day, his wage increases by th...
- by aarati
Tue Aug 10, 2010 11:37 pm- Forum: Problem Solving
- Topic: wages earned
- Replies: 2
- Views: 893
Jinglander wrote:p and q are different two-digit prime numbers with the same digits, but in reversed order. What is the value of the larger of p and q?
(1) p + q = 110
(2) p – q = 36
Answer C
please check your OA once ..... the answer is D
- by aarati
Tue Aug 10, 2010 11:15 pm- Forum: Problem Solving
- Topic: Wow hard number properties
- Replies: 4
- Views: 2259
Plug values into each answer choice. Eliminate any answer choice that doesn't give us a factor that is a multiple of 3. Plug in n=7: A) 7*8*3. Since 3 is multiple of 3, hold onto A. B) 7*9*6. Since 9 and 6 are each a multiple of 3, hold onto B. C) 7*10*2. Since neither 7 nor 10 nor 2 is a multiple ...
- by aarati
Tue Aug 10, 2010 10:39 pm- Forum: Problem Solving
- Topic: prime & divisibility
- Replies: 3
- Views: 1025
Original A:B:W = 4:15:20. B = 30, so actual values of A, B and W are all doubled: A = 8 B = 30 W = 40 New ratio of A:B = 3:5 Unchanged ratio of A:W = 4:20 = 1:5 = 3:15 (Since A is common to each ratio, we want A to be represented by the same number in each ratio so that the ratios can be combined.)...
- by aarati
Tue Aug 10, 2010 10:28 pm- Forum: Problem Solving
- Topic: Ratios and Mixtures
- Replies: 10
- Views: 4598