two consecutive odd positive integers

Find two consecutive odd positive integers, sum of whose squares is 290.

(a) 19,17
(b) 23,27
(c) 11,-13
(d) 7,9


help me to solve it.......

nithi_mystics wrote:Total time taken = 840/60 = 14 hours.

The train reached Chicago at 6 PM. So it should have started Newyork at 4 AM (Chicago time) ie., 5 AM NewYork time.

Solution: nPr is n!/(n-r)! and nCr is n!/{r!*(n-r)!}. So nPr/nCr is r! which is 30240/252 = 120 = 5! So r is 5. We need not look for n because in all options there is only one choice where r is 5. Correct answer is (10,5). thank u ..... you said u must ignore n because in all options there is only ...

Hi, Unlikely to be GMAT level ... x - 3 = (2/(3+sqrt{7})) - 3 = (-7-3sqrt(7))/(3+sqrt(7)) Squaring the previous term will lead to 7. thank u very much... can u explain me in step by step procedure please.... In problems like these, you have to rationalize the denominator i.e. make it into an intege...

Find the exponent of 3 in 100!. please help me to solve it............ Divide 100 by powers of 3 to get the exponent of 3 in 100! 100/3 = 33 100/9 = 11 100/27 = 3 100/81 = 1 Hence exponent of 3 = 33+11+3+1 = 48 Hope this helps!! thank u very much .......i understood how to solve it.......you are si...

4GMAT_Mumbai wrote:Hi,

Unlikely to be GMAT level ...

x - 3 = (2/(3+sqrt{7})) - 3

= (-7-3sqrt(7))/(3+sqrt(7))

Squaring the previous term will lead to 7.

Jinglander wrote:p and q are different two-digit prime numbers with the same digits, but in reversed order. What is the value of the larger of p and q?

(1) p + q = 110
(2) p – q = 36

Answer C

Original A:B:W = 4:15:20. B = 30, so actual values of A, B and W are all doubled: A = 8 B = 30 W = 40 New ratio of A:B = 3:5 Unchanged ratio of A:W = 4:20 = 1:5 = 3:15 (Since A is common to each ratio, we want A to be represented by the same number in each ratio so that the ratios can be combined.)...