Search found 22 matches
- by smashinonions
Fri Sep 26, 2008 6:57 am- Forum: Problem Solving
- Topic: Distance, Time & Rate
- Replies: 4
- Views: 1517
- by smashinonions
Fri Sep 26, 2008 6:54 am- Forum: Problem Solving
- Topic: GMAT Prep -Sets II
- Replies: 2
- Views: 1411
- by smashinonions
Fri Sep 26, 2008 6:53 am- Forum: Problem Solving
- Topic: GMAT Prep -Sets
- Replies: 4
- Views: 1597
- by smashinonions
Fri Sep 26, 2008 4:24 am- Forum: Problem Solving
- Topic: GMAT Prep - 2
- Replies: 5
- Views: 1622
- by smashinonions
Fri Sep 26, 2008 4:24 am- Forum: Problem Solving
- Topic: GMAT Prep - 1
- Replies: 1
- Views: 1362
- by smashinonions
Sat Jul 05, 2008 10:05 am- Forum: Problem Solving
- Topic: GMATprep PS question
- Replies: 4
- Views: 1572
can it also be done as below:
4 machines take 6 hrs for 5000 pgs so
1 machine will take 24 hrs for 5000 pgs
therefore,
3 machines will take 8 hrs for 5000 pgs
for 3000 pages 3 machines will take 5000/ 3000 * 8 = 4 hr 48 mins
- by smashinonions
Sat Jul 05, 2008 9:09 am- Forum: Problem Solving
- Topic: PS5 Last one
- Replies: 2
- Views: 1316
- by smashinonions
Sun Jun 29, 2008 5:57 pm- Forum: Problem Solving
- Topic: GMAT Prep - Circles
- Replies: 3
- Views: 1621
total length = pi * r + pi * r + 2 L (distance between the two centers)
total length = 15 (given)
15 = 2 * pi * 0.5 + 2 L
then L = 15 - pi / 2 (ans)
- by smashinonions
Sat Jun 28, 2008 9:27 pm- Forum: Problem Solving
- Topic: GMAT Prep - Circles
- Replies: 3
- Views: 1621
another way
well, the range of numbers is from 0 - 50 so we have (50 -0) + 1 = 51 numbers but the last number that has a remainder of 1 when divided by 3 is 49 ( 49 / 3 = 16 with remainder 1) now, here the numbers from 0 - 50 which leave a remainder of 1 when divided by 3 can be written as 1, 4, 7, 10, 13... he...
- by smashinonions
Tue Jun 24, 2008 11:12 pm- Forum: Problem Solving
- Topic: any shorter method to solve this
- Replies: 14
- Views: 3109
for the set of given numbers the avg is 4 and the SD is sqrt (10)
so among the given ans only (A) is close to the SD of 10
I solved it by plugging in choices.
- by smashinonions
Mon Jun 23, 2008 6:51 pm- Forum: Problem Solving
- Topic: sd
- Replies: 5
- Views: 1923
the ratio of the sides of two similar triangles is equal to the sqrt of the ratio of their areas is the rule which is if triangles A1 and A2 have sides S1 and S2 and areas Ar1 and Ar2 then, S1 / S2 = Sqrt ( Ar1 / Ar2) pls visit http://www.mathopenref.com/similartrianglesareas.html for more details :)
- by smashinonions
Mon Jun 23, 2008 3:12 pm- Forum: Problem Solving
- Topic: GMAtprep question
- Replies: 11
- Views: 2543
ans
http://www.mathopenref.com/similartrianglesareas.html for similar triangles, side = Sqrt (area) let s = a (area) and S= A (area) given, A = 2a also, s / S = sqrt(a)/ sqrt(2a) or S = Sqrt(2a) * s/ sqrt(a) = Sqrt (2a) Sqrt (a) * s/ Sqrt (a) * sqrt (a) [simplification] = sqrt (2) * s (ANS)
- by smashinonions
Sun Jun 22, 2008 6:53 pm- Forum: Problem Solving
- Topic: GMAtprep question
- Replies: 11
- Views: 2543
ans
Let X1, X2, X3 be the 3 readings so, X1 + X2 + X3 / 3 = 8 or X 1 + X2 + X3 = 24 so as the range is from 0- 10 to find the min qty measured, we maximize the remaining two i.e X1 (assuming to be smallest) = 24 - (X2 + X3) = 24 - (10 + 10) [ 10 being the max value that the meter can read) = 4
- by smashinonions
Sun Jun 22, 2008 6:25 pm- Forum: Problem Solving
- Topic: GMAtprep question
- Replies: 2
- Views: 1440
ans
P + K + M = 162
given,
P = 2K ---- A
P = 1/3 M ----- B
from A and B,
2K = 1/3 M
or M = 6K
now,
2K + K +6K = 162
or K = 18
and M = 6K = 6 * 18 = 108
so M - K = 108 -18 = 90 (ANS)
- by smashinonions
Sun Jun 22, 2008 5:53 pm- Forum: Problem Solving
- Topic: Basic Algebra
- Replies: 1
- Views: 1415