Hi rb90: I have a different approach, we can derive the following equation from the question stem 50% * (1-x) + 30%x = 40%*1 ( where x is the fraction amount replaced and 1 is the entire solution) Solving for x: .5 - .5x + .3x = .4 or, -.2x = -.1 or, x = .1/.2 or, x=1/2 I think it works. Thanks.

Thanks Sarwan. I think we don't need to insert one/two other variables to find out "days". The question asked for the price when they will be same. And definitely the price has to be same after the same number of days since the increasing and decreasing is taking place at constant rate. Th...

If the answer is E then the question needs little modification, I am not sure though. Instead of the price of wheat decreasing at a rate "square root (2x)-x" it needs to be "square root(2)x-x". If considered the latter one the problem can be solved in the following way: 320 + 5x ...

Answer is E.

x = 1, Y = -1

solve for (x-y)/(x+y)= 2/0 which is undefined, so the answer is E.

Singly both the statements are not sufficient as well.

I think its E.

2^3>4

in this case

x<y

Yes Jaskaran, you are right. its e.

thanks.

algebra

what is the value of a^2+b^2?

i. a=4-b
ii. b=1/a

b/a = 3^n+1/2^n+1
= (3.3^n)/(2.2^n)=(3/2)(3^n/2^n)=1.5(3^n/2^n)

now, since n is positive integer n=1,2,3....
for n= 1 the value stands for 1.5*1.5=2.25 which will go up if we set n=2,3,4,...

so answer is A.

Is my method ok?