Search found 576 matches
From 2 13n=mk or n=mk/13 since 3<m<13,k/13 has to an integer so that mk/13 is integer..sufficient Ans option B 13n=mk or n=mk/13 here LHS(n) is integer so RHS has to be integer i.e mk/13 is integer now m<13 and 13 is a prime so only way mk/13 is an integer when k/13 is integer. Why cant we apply th...
- by liferocks
Tue Jun 08, 2010 7:16 am- Forum: Data Sufficiency
- Topic: Rooms-Students assignment
- Replies: 9
- Views: 1480
From 2 13n=mk or n=mk/13 since 3<m<13,k/13 has to an integer so that mk/13 is integer..sufficient Ans option B Hi, I understood why the first statement is insufficient. But the second statement is confusing. Can you please tell me why k/13 has to be an integer? 13n=mk or n=mk/13 here LHS(n) is inte...
- by liferocks
Tue Jun 08, 2010 6:16 am- Forum: Data Sufficiency
- Topic: Rooms-Students assignment
- Replies: 9
- Views: 1480
From 1
3n=mk where k is any integer
or n=mk/3 now k/3 may or may not be integer depending on which n may or may not be a multiple of m..insufficient
From 2
13n=mk or n=mk/13
since 3<m<13,k/13 has to an integer so that mk/13 is integer..sufficient
Ans option B
- by liferocks
Tue Jun 08, 2010 4:59 am- Forum: Data Sufficiency
- Topic: Rooms-Students assignment
- Replies: 9
- Views: 1480
in the room 2 pairs of sibling and 3 siblings are present if 2 individuals so that they are siblings can be done by selecting any one of the 2 pair in 2 ways any any 2 of the 3 siblings in 3C2=3 ways Total 5 ways 2 people can be selected out of 7 in 7C2=21 ways so If two individuals are selected fro...
- by liferocks
Tue Jun 08, 2010 3:43 am- Forum: Problem Solving
- Topic: Probability
- Replies: 9
- Views: 1817
from 1 we get x=7k and y=9k so depending on whether k>0 or k<0 x>y or x<y..insufficientallfta wrote: is x<y ? (sorry this is DS)
1) the ratio of x to y is 7/9
2) xy>0
from 2 we get both x,y has same sign..nothing can be concluded..insufficient
ans option E
- by liferocks
Tue Jun 08, 2010 3:36 am- Forum: Problem Solving
- Topic: tricky PS - four quetions.
- Replies: 6
- Views: 1404
The operation @ is defined by x@y = 1/x + 1/y for all nonzero numbers x and y. if z is a number greater than 1, which of the following must be true? 1) z @ (-z) = 0 2) z @ z/z-1 = 0 3) 2/z @ 2/z =zd A 1 B 1,2 C 1,3 D 2,3 E all lets take z=3/2 so -z=-3/2..so z @ (-z) =2/3 - 2/3=0..correct z/z-1 =3/2...
- by liferocks
Tue Jun 08, 2010 3:30 am- Forum: Problem Solving
- Topic: tricky PS - four quetions.
- Replies: 6
- Views: 1404
Three pieces of wire have a median length of 48 inches. The other two wires' length are 44 and 48. What is the median? Is it 48 or 46(median of 44 and 48) or just average? (This question is not a complete one. Sorry) 2)In the same manner, what is the median number of 44 45 45 48 48 ? median is the ...
- by liferocks
Tue Jun 08, 2010 3:23 am- Forum: Problem Solving
- Topic: tricky PS - four quetions.
- Replies: 6
- Views: 1404
d= 1/2^3 x 5^7allfta wrote:2. If d= 1/2^3 x 5^7 is expressed as a terminating decimal, how many nonzero digits will d have?
=1/(2*5)^3 * 25*25
=(1/1000)*(4/100)*(4/100)
=16/10000000
so non zero digits are 1 and 6..ans 2
- by liferocks
Tue Jun 08, 2010 3:22 am- Forum: Problem Solving
- Topic: tricky PS - four quetions.
- Replies: 6
- Views: 1404
Hi guyz. Would u explain these questions? 1. The points R, T, and U lie on a circle that has radius 4. If the length of arc RTU is 4pai/3, what is the length of line segment RU? 2*pi*4 arc lenght makes an angle of 360 degree at center of the cisrcle so 4pai/3 arc lenght makes an angle of 360*4pi/(3...
- by liferocks
Tue Jun 08, 2010 3:20 am- Forum: Problem Solving
- Topic: tricky PS - four quetions.
- Replies: 6
- Views: 1404
in another way , probability that both representatives selected will be men<1/10 so number of men can be 0,1,2,3 probability that both representatives selected will be men=3/45 if number of men is 3,probability that one of the representative selected will be women and another will be men = (3*7)/45 ...
- by liferocks
Tue Jun 08, 2010 2:12 am- Forum: Problem Solving
- Topic: If 2 different representatives are to be selected at random
- Replies: 12
- Views: 8478
from question P= 1-(probability that both representatives selected will be men+probability that one of the representative selected will be women and another will be men) from 2 probability that both representatives selected will be men<1/10 but no information for 'probability that one of the represe...
- by liferocks
Tue Jun 08, 2010 2:08 am- Forum: Problem Solving
- Topic: If 2 different representatives are to be selected at random
- Replies: 12
- Views: 8478
Lets dan's body weight is 100x
so class A body weight is 100x+100x*8/100 =108x
class B body weight is 100x-8x=92x
so a class A needs to loose (108-92)x or 16x to perform in class B
this is 16/108 *100% of class A weight 4*100/27 or 400/27 or 14.81%
- by liferocks
Tue Jun 08, 2010 1:43 am- Forum: Problem Solving
- Topic: percents problem totally confusing!!
- Replies: 6
- Views: 3167
p% of 20=20p/100
p% of 60=60p/100
so,
20+20p/100=60-60p/100
or 80p/100=40
or p/100=1/2
p% of 70=70 * p/100 =70 * 1/2 =35
Ans 35
- by liferocks
Mon Jun 07, 2010 11:06 pm- Forum: Problem Solving
- Topic: simple but confusing
- Replies: 4
- Views: 1386
IMO ans is B argument is effect of the save manatee effort might not be successful. Last year, several manatees were mysteriously killed by an unidentified toxin .--out of scope All manatees swim at depths that make them vulnerable to the blades of motorboat engines.--if this is true then even if pe...
- by liferocks
Mon Jun 07, 2010 9:23 pm- Forum: Critical Reasoning
- Topic: MGMAT question
- Replies: 13
- Views: 2619
- by liferocks
Mon Jun 07, 2010 9:15 pm- Forum: Critical Reasoning
- Topic: Medical Students
- Replies: 11
- Views: 2343