Search found 9 matches
- by sdas0112
Fri Jul 08, 2011 2:07 pm- Forum: Data Sufficiency
- Topic: Veritas Prep Challenge Question
- Replies: 21
- Views: 3555
- by sdas0112
Fri Jul 08, 2011 11:03 am- Forum: Sentence Correction
- Topic: Veritas Prep Challenge Question SC #2
- Replies: 10
- Views: 1739
Answer B.
C:W = 20:7
C:M = 15:3
If M:C doubled, new C:M = 15:6
Combined Ratio W:C:M = 21:60:24
Ratio of Children:Adults = 60:(21+24) = 60:45 = 4:3
- by sdas0112
Thu Jul 07, 2011 5:30 pm- Forum: Problem Solving
- Topic: Veritas Prep Challenge Question
- Replies: 14
- Views: 2354
My answer is C as stated above.... I answered using a mobile device, where the lines were shorter and were shown as 2-3 and 10-11 but on my laptop browser, it looks like its line 1 and 3-4.
- by sdas0112
Thu Jul 07, 2011 2:51 pm- Forum: Critical Reasoning
- Topic: Veritas Prep Challenge Question
- Replies: 27
- Views: 3675
- by sdas0112
Thu Jul 07, 2011 2:18 pm- Forum: Critical Reasoning
- Topic: Veritas Prep Challenge Question
- Replies: 27
- Views: 3675
- by sdas0112
Thu Jul 07, 2011 11:44 am- Forum: Sentence Correction
- Topic: Veritas Prep Challenge Question
- Replies: 25
- Views: 3783
Ans A)
a)
(x+y)^2 = 4xy
=>(x--y)^2 = 0
=> x-y = 0
Sufficient
b) x^2-y^2 = 0
=> (x-y)(x+y)=0
NOT SUFFICIENT
- by sdas0112
Thu Jul 07, 2011 11:30 am- Forum: Data Sufficiency
- Topic: Veritas Prep Challenge Question
- Replies: 21
- Views: 3555
- by sdas0112
Mon Nov 22, 2010 8:10 am- Forum: Sentence Correction
- Topic: Parallel structure: confusing
- Replies: 37
- Views: 22015
Frankie and Joey need to be together .. treat them as one, so 5 mobsters can be arranged in 5! ways.
Frankie and Joey amongst themselves can be arranged in 2! ways
So 5!*2! = 480
- by sdas0112
Fri Nov 12, 2010 8:27 am- Forum: Problem Solving
- Topic: Counting - Six mobsters
- Replies: 59
- Views: 27911