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Another way to approach these questions is to start on either end of the range and work your way to the middle. 1) Sum of all even numbers from 1 to 199 Consider the first even number greater then 1 and first even number smaller then 199, so 2 + 198 =200 Then the second even number greater then 1 an...
- by sk02
Wed Nov 25, 2009 9:46 pm- Forum: GMAT Math
- Topic: sum of all even numbers from 99 to 301
- Replies: 19
- Views: 80391
Not sure if this is the easiest answer, but if you group the 2s and 3s, it should help to identify the ans:
(2^5+2^5)+(3^5+3^5+3^5)
= 2(2^5) + 3(3^5)
= 2^6 + 3^6
so ans C.[/list]
- by sk02
Tue Nov 10, 2009 10:42 pm- Forum: Problem Solving
- Topic: Arithmetic Exponents
- Replies: 3
- Views: 1373
Permutation question
Hi, could someone provide a more detailed answer for the following permutation question: Q. How many six-letter sequences consisting of 1A, 2Bs and 3Cs are possible? The answer guide gave the following: If all letters in sequence different, 6! sequences possible. But, arrangement of 2Bs and 3Cs need...
- by sk02
Sun Nov 08, 2009 9:59 pm- Forum: Problem Solving
- Topic: Permutation question
- Replies: 2
- Views: 1570