I’d go with C 1. y = x + 1 Xy = x(x+1) Xy = x^2+x Insuff. 2. y = x^2+1 Xy = x(x^2+1) Xy = X^3+x Insuff. 1+2 X+1 = x^2+1……………or x = x^2 0 = X^2 – x 0 = X(x-1) Case 1: x = 0 Then XY must equal 0 Case 2: x-1=0…………………….or x = -1 Plug this back into first equation y = x+1 Y ...

Re: 740

Hi, I bought OG-11 in the mid of April. First I did the diagnostic test in OG. I found that my quant was excellent ( :P ) but the lowest rating was for SC. Great score. Congratulations. Glad to see hard work pay off like this. You mentioned that you did not have much trouble with quant from the beg...

shanrizvi wrote: I think the key point here is that statement 1 is sufficient because m is between 3 and 12 and there are multiples of 3 in that range but not multiples of 13.

Appreciate the reply. I cancelled becuase I was simply not comfortable with the number of questions on which I guessed. I completely guessed on at least 12 problems. Furthermore, I did not have much confidence in at least 6 or 7 more problem that I did get through. Again, remember that I had taken t...

trooper,

Awesome score. If you don't mind me asking, do you have some type of background in Math? Or does math just comes easy to you? Also, may be I missed it but how many weeks/months did you spend preparing for the math section?

Thanks in advance.

Can you post the source of this question?

Q, Is X -ve number?? 1, 9x > 10x 2, x+3 is +ve Just divide the first inequality by X. If x is positive We get: 9 > 10. Which is not possible x must be negative because the sign would flip when dividing by a negative number. 9 < 10. Suff. 2. x + 3 > 0 x > -3 X can be any number, positive or negative ...

Could you please provide the source of the question so that we can avoid it?