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Re: 500 ds
Ans is B I'll explain... Let the height of point B is h and the point is H. Let the length of seesaw ie AC is 2d.. Now draw perpendicular lines to ground from point B and C. Let they intersect at ground at D ( from Point B) & E(point C). Now we will get two similar triangles.. ie ABD and ACE.. w...
- by myprepgmat
Sat Apr 07, 2007 5:06 am- Forum: Data Sufficiency
- Topic: 500 ds
- Replies: 6
- Views: 4071
Re: 500 ds test4 #20
No need to calculate the value of k. we can approach the question in a different way 1) k - 1/k =1 multiply with k gives k^2 - 1 =k now rearraange K^2-k =1 >>Ans Now take case 2) 2k-1 = root5 Square the equation ie (2k-1)^2 =5 i.e. 4k^2-4k+1=5 4k^2-4k-4=0 (after re-arranging) Divide by 4 >> k^2-k-1=...
- by myprepgmat
Sat Apr 07, 2007 4:47 am- Forum: Data Sufficiency
- Topic: 500 ds test4 #20
- Replies: 3
- Views: 3142