Search found 14 matches
- by Badri
Tue Oct 16, 2007 9:09 am- Forum: Problem Solving
- Topic: GMAT prep Q
- Replies: 3
- Views: 1712
Thanks for the theorem!
I think you made a small error ..
H(100) is not 100! but 2* 50!
I got p=51..can u please recheck
- by Badri
Tue Oct 16, 2007 8:16 am- Forum: Problem Solving
- Topic: Gmat prep Q
- Replies: 5
- Views: 2175
So, If I understand you correctly, if we use "had" only once, then both events would be in the past tense and that would not set up a correct time relation.
So "had had" achieves that.....got it! ...Thanks
- by Badri
Sun Apr 01, 2007 8:03 pm- Forum: Sentence Correction
- Topic: Past Perfect Tense
- Replies: 4
- Views: 4471
Past Perfect Tense
In the following sentence, is the use of "had" twice correct?
If she had had more money, she would have bought a bigger house.
I feel it should be used only once. Is there a specific rule for such sentences. This appeared in one of the grammar books.
- by Badri
Sun Apr 01, 2007 2:58 pm- Forum: Sentence Correction
- Topic: Past Perfect Tense
- Replies: 4
- Views: 4471
I think OG is the most representative. We keep practicing from n number of resources and ultimately may ignore or underestimate the most representative resource- OG. I know a high scorer who did OG 20 times (no exaggeration) with explanations of both right and wrong answers!
- by Badri
Thu Mar 29, 2007 2:16 pm- Forum: Critical Reasoning
- Topic: lsat cr vs gmat cr
- Replies: 1
- Views: 3703
- by Badri
Thu Mar 29, 2007 8:56 am- Forum: Data Sufficiency
- Topic: GMAT Prep Test Q
- Replies: 5
- Views: 4076
- by Badri
Sun Mar 25, 2007 7:02 pm- Forum: Sentence Correction
- Topic: GMAT Prep Question
- Replies: 6
- Views: 2754
Assuming: PO = x and QO = y x.x - 15.15 = y.y - 6.6 (equating the Perpendicular from O on PR) => (x+y).(x-y) = (15+6).(15-6) = 21.9 = 21.3.3 = 7.3.3.3 Since x and y are integers hence their 'addition' and 'difference' will also be integer Therefore: Sol1: *Since, O is not on PR hence (x+y) = 21 and ...
- by Badri
Mon Mar 12, 2007 5:41 am- Forum: Problem Solving
- Topic: Discuss the toughest problem solving questions.
- Replies: 9
- Views: 6094
the assumption : "...the only way is if they are arranged in the 3rd and 4th position ..." is not quiet right. Barring '5' we have '1', '2', '3', '4', '6', '7' and we need to select group of 5 out of these 6 models. Now Since '4' and '6' must be selected to violate the rule; so, we need to...
- by Badri
Fri Mar 09, 2007 7:22 pm- Forum: Problem Solving
- Topic: Counting problem
- Replies: 6
- Views: 3491
Assuming that the balls are not replaced in the basket after drawing: There are three ways the incident can happen: ----1st Ball----2ndBall----3rd Ball---Probability (1) Red--------Red--------Green-----P1 = ( 7/10 )*( 6/9 )*( 3/8 ) (2) Red--------Green------Red-------P2 = ( 7/10 )*( 3/9 )*( 6/8 ) (3...
- by Badri
Fri Mar 09, 2007 4:13 pm- Forum: Problem Solving
- Topic: PowerPrep Problem
- Replies: 7
- Views: 4676
its a tricky Question Start with the innermost '$' operation innermost : $(15) = 14 ; even !!! next : $(14) = 16 ; even !!! next : $(16) = 18 ; even !!!! ...... . . . . 98 times Final answer = 14 + (2 + 2 + 2 + ....... 98 times) = 14 + ( 2*98 ) = 14 + 196 = 210 So the correct answer is (c) 210
- by Badri
Fri Mar 09, 2007 11:15 am- Forum: Problem Solving
- Topic: Difficult Math Problem #107 - Algebra
- Replies: 7
- Views: 2585
well 10C2 is obviously a correct choice because:
here order does not matter. Person '1' shaking hand with person '2' and person '2' shaking hand with person '1' are same events hence
10P2/(!2) = 10C2
- by Badri
Fri Mar 09, 2007 10:59 am- Forum: Problem Solving
- Topic: Difficult Math Problem #106 - Combinations
- Replies: 11
- Views: 8565
A correction !!!
Please correct my previous answer: 99th Percentile: (99/100)*15 = 14.85 --> the 15th number (45) is the 99th percentile [14.85 numbers (99%) are EQUAL OR below the 15th number] 80th Percentile: (80/100)*15 = 12 --> 12 th number ( 37 ) is 80th percentile [12 numbers (80%) are EQUAL OR below the 12 th...
- by Badri
Fri Mar 09, 2007 10:50 am- Forum: Problem Solving
- Topic: Percentile
- Replies: 3
- Views: 37286
Calculating the percentile
Generally: In a distribution X is n-th percentile if at least n% of the numbers in the distribution sample are less than or equal to X. For example: (1) Consider the number sequence 21, 22, 20, 34, 33, 23, 30, 27, 28, 29, 37, 36, 45, 40, 43 We have 15 numbers. We wish to find what is 99th percentile...
- by Badri
Fri Mar 09, 2007 9:22 am- Forum: Problem Solving
- Topic: Percentile
- Replies: 3
- Views: 37286