Search found 12 matches
The correct answer is 11.
13456
13457
13467
13567
14567
23456
23457
23467
23567
24567
34567
(The numbers 1-7 represent the 7 execs, where 1 is the CEO and 2 the CFO.)
From my point of view the easiest way to solve this question is to write down all possible solutions.
- by patrik.herzog
Tue Dec 11, 2007 8:11 am- Forum: Problem Solving
- Topic: PS combinations,manhattan
- Replies: 4
- Views: 1607
Divisors of
10 = 1, 2, 5, 10
20 = 1, 2, 4, 5, 10, 20
Prime divisors of 10 and 20 are: 2, 5
Now, do it for the rest of the pairs and you'll see that all except 24 and 32 have at least 2 identical prime divisors..
Hence, answer C
- by patrik.herzog
Wed Sep 19, 2007 5:02 am- Forum: Problem Solving
- Topic: Section - 22 Question - 10
- Replies: 5
- Views: 2517
Hmm.. from my point of view the remainder could be 0, 1, 3 or 4
Is the phrasing of the question correct??
- by patrik.herzog
Tue Sep 18, 2007 6:03 am- Forum: Problem Solving
- Topic: Scoretop 31 - Question 25 - Remainder
- Replies: 4
- Views: 1560
The correct answer is A Here's an example: Low 1982 = 20; 1995 = 40 Med 1982 = 10; 1995 = 18 High 1982 = 10; 1995 = 22 Total 1982 = 40; 1995 = 80 Low: Greatest increase in numbers (20), but no increase in share High: Increase in share (from 25% to 27.5%), but not greatest increase in numbers (12) An...
- by patrik.herzog
Wed Sep 12, 2007 5:05 am- Forum: Critical Reasoning
- Topic: 1000 Cr - Test 5 , q 19
- Replies: 6
- Views: 2763
E
x = side of the square
x^2 = (x+30)(x-20)
x^2 = x^2 -20x +30x -600
x^2 = x^2 +10x -600
10x = 600
x = 60
Hence, the answer is E
- by patrik.herzog
Wed May 02, 2007 12:58 am- Forum: Problem Solving
- Topic: test40 #10
- Replies: 2
- Views: 1632
Factorize
Hi,
you have the factorize the number 147000
147000 = 147 x 1000
147 = 3 x 7 x 7
1000 = 5 x 5 x 5 x 2 x 2 x 2
hence, the following number of beads were removed:
Red 2
Yellow 3
Green 1
Blue 3
- by patrik.herzog
Mon Apr 30, 2007 11:46 pm- Forum: Problem Solving
- Topic: test 38 #15
- Replies: 3
- Views: 1781
I still don't get it..
OK, with z=0 or x=1 we have a solution.
But what about x=0 and z=0? Why isn't that true?
Thanks a lot!
- by patrik.herzog
Thu Mar 29, 2007 5:27 am- Forum: Problem Solving
- Topic: GMAT Prep Question
- Replies: 13
- Views: 3275
- by patrik.herzog
Wed Mar 28, 2007 5:52 am- Forum: Problem Solving
- Topic: GMAT Prep Question
- Replies: 13
- Views: 3275
For my point of view, there are 4 possible answers.. a) could be correct x=0 and z=0 -> 0 = 0 b) could be correct x=1 and y=1 -> 1 + z = 1 + z c) could be correct y=1 and z=0 -> x = x b) wrong x=1 or y=0 -> y+z = y + Z -> z = xz e) could be correct x=1 or z=0 -> y+z = y+z -> xy = xy
- by patrik.herzog
Wed Mar 28, 2007 4:00 am- Forum: Problem Solving
- Topic: GMAT Prep Question
- Replies: 13
- Views: 3275
- by patrik.herzog
Tue Mar 27, 2007 11:48 pm- Forum: Problem Solving
- Topic: GMAT Prep - Library books
- Replies: 4
- Views: 2126
GMAT Prep Question
I can't get the following question:
If xy + z = x(y+z), which of the following must be true
x=0 and z=0
x=1 and y=1
y=1 and z=0
x=1 or y=0
x=1 or z=0
Thanks for any help on this!
- by patrik.herzog
Tue Mar 27, 2007 11:44 pm- Forum: Problem Solving
- Topic: GMAT Prep Question
- Replies: 13
- Views: 3275
Nr5
Nr 5 is quite easy. The mean should be 21 (instead of 12)
21 - 6 = 15 (6 = 1 Standard Deviation)
21 - 12 = 9 (12 = 2 Standard Deviations)
So, Pat watch between 9 and 15 hours TV last week. (Ans > 12)
- by patrik.herzog
Wed Mar 21, 2007 6:53 am- Forum: Problem Solving
- Topic: GMAT Prep 6 questions – I don't know how to solve them
- Replies: 20
- Views: 10703