Search found 45 matches
Can somebody explain why the following method does not produce the correct answer? Largest number must be 7, 8 or 9 so 1/3 prob. Second largest must be 6. 1/8 prob. Third must be 1, 2, 3, 4, or 5 and 7 are left...so 5/7 prob The forth would be 4/6 prob And the last number has to be 3/5 prob so (1/3)...
- by 720dreaming
Thu Jan 29, 2009 5:16 pm- Forum: Problem Solving
- Topic: Probability/counting - select 5 numbers ...
- Replies: 11
- Views: 1869
Depends on their positions. Draw it out. 20<------Pam---5---Ed------>20 Total=45 + (pam & ed)=47 Or 14<-----Ed---5----P------->14 Total=33 + (pam & ed)=35 Hence, E. Btw, even if you screw up 14 and put 15 instead (which I did initially, forgetting pam and ed) you would still get E. Main poin...
- by 720dreaming
Fri Jan 16, 2009 8:08 pm- Forum: Data Sufficiency
- Topic: Line
- Replies: 1
- Views: 1311
- by 720dreaming
Fri Jan 16, 2009 1:32 pm- Forum: Problem Solving
- Topic: 2 ques
- Replies: 8
- Views: 2430
- by 720dreaming
Thu Jan 15, 2009 11:33 am- Forum: Data Sufficiency
- Topic: Problem on Multiples
- Replies: 8
- Views: 1780
I definitely understand the OP's problem with this question.
I realize this is gmat prep so I can't say this is an strange question, but at the same time it seems that the question stem should let us know if they do or do not have overlapping membership. Or at least hint at that possibility.
- by 720dreaming
Thu Jan 15, 2009 7:35 am- Forum: Data Sufficiency
- Topic: Drama and music !
- Replies: 3
- Views: 1289
I'll go with D. A) Since (x+1) is divisible by 3, we know that (X+1)(X-5) is divisible by 3. This gives us x^2-4x-5. This is divisible by 3. To get the equation in the question we need to add 16. Since 15 is divisble by 3, the R=1. Sufficient. B)Similar logic to above. (x-2)(x-2) is divisible by 3. ...
- by 720dreaming
Thu Jan 15, 2009 7:12 am- Forum: Data Sufficiency
- Topic: Remainder when divided by 3
- Replies: 3
- Views: 1326
I got A, 1/126. Here is my logic. First girl picks a marble. Prob 1. Second girl must pick the same color marble. Prob (4/9) Third girl must pick the same color marble. Prob (3/8) Fourth girl must pick the same color marble. Prob (2/7) Fifth girl must pick the same color marble. Prob (1/6) So.... 1*...
- by 720dreaming
Wed Jan 14, 2009 8:08 am- Forum: Problem Solving
- Topic: Probability - 10 marbles
- Replies: 143
- Views: 55373
- by 720dreaming
Tue Jan 13, 2009 7:01 pm- Forum: Data Sufficiency
- Topic: Probability DS
- Replies: 9
- Views: 1884
Thanks Logitech. I am aware of the formula, but I am not sure if its relevent here. A gives the prob of both events occuring. I would think that one EventA*EventB=prob of both events occuring. For example, if the prob of event A is (.6) and prob of event B is (.2) is the prob of both events occuring...
- by 720dreaming
Tue Jan 13, 2009 6:20 pm- Forum: Data Sufficiency
- Topic: Probability DS
- Replies: 9
- Views: 1884
- by 720dreaming
Tue Jan 13, 2009 12:09 pm- Forum: Data Sufficiency
- Topic: Probability DS
- Replies: 9
- Views: 1884
Sorry for the delayed response, took a few days off. I used the OG and MGMAT practice tests. Honestly, i did not really study for the verbal since i was doing well enough in the practice tests. However, as I said, i found the verbal to be much harder. At this point, I will probably get the mgmat CR ...
- by 720dreaming
Sun Dec 28, 2008 1:33 am- Forum: GMAT Strategy
- Topic: Scheduling a GMAT test
- Replies: 4
- Views: 1564
Which materials did you use to study?
A similar thing happend with me. Higher math, significantly lower verbal.
Found the math a bit easier than I practiced, but the verbal much harder.
- by 720dreaming
Tue Dec 23, 2008 10:53 am- Forum: GMAT Strategy
- Topic: Scheduling a GMAT test
- Replies: 4
- Views: 1564
- by 720dreaming
Sat Dec 20, 2008 7:53 pm- Forum: Data Sufficiency
- Topic: algebra
- Replies: 21
- Views: 3473
Used the same method as above, same answer. However, I was not sure about A: How can we be sure that both X and Y are integers? If we know that X is an Integer I think its safe to assume that Y is also...and vice versa. But, in A, we don't know that... For now, I suppose we can just assume that the ...
- by 720dreaming
Sat Dec 20, 2008 7:15 pm- Forum: Data Sufficiency
- Topic: algebra
- Replies: 21
- Views: 3473
I was expecting someone to correct my logic, something was missing in the question (based on my intuition), but formula SEEMED to work.
Thanks.
- by 720dreaming
Sat Dec 20, 2008 10:31 am- Forum: Data Sufficiency
- Topic: Cars and students
- Replies: 10
- Views: 1856