Search found 1 match
Imagine a polygon of 16 sides. Each vertex stands for one team. Draw all the diagonals. Each side / each diagonal stands for a match between two teams (two vertices at the two end of the line) Hence total no of matches = total no of diagonals + no of sides = n(n-3)/2 + n
- by KAUSTAV89
Sun Oct 16, 2016 3:21 am- Forum: Problem Solving
- Topic: Soccer time
- Replies: 35
- Views: 17662