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Imagine a polygon of 16 sides. Each vertex stands for one team. Draw all the diagonals. Each side / each diagonal stands for a match between two teams (two vertices at the two end of the line) Hence total no of matches = total no of diagonals + no of sides = n(n-3)/2 + n

by KAUSTAV89

Sun Oct 16, 2016 3:21 am
Forum: Problem Solving
Topic: Soccer time
Replies: 35
Views: 17662