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For any positive integer n, the sum of the first n integers equals n(n+1)/2. What is the sum of all the even integers between 99 and 301. Would like a very thorough explanation of this problem. You don't need to follow the formula. Just go by the simple method, i.e, sum = Average* no. of terms Aver...
- by shwetagoyal121
Mon May 30, 2016 3:43 am- Forum: Problem Solving
- Topic: Consecutive Integers
- Replies: 10
- Views: 7903
Answer: A (Method: rationalize)Max@Math Revolution wrote:1/(9-4√5)=?
A. 9+4√5
B. 9-4√5
C. 9+2√5
D. 9-2√5
E. 4+9√5
*An answer will be posted in 2 days.
- by shwetagoyal121
Mon May 30, 2016 2:24 am- Forum: Problem Solving
- Topic: 1/(9-4√5)=?
- Replies: 3
- Views: 2957
If n is a positive integer and the product of all the integers from 1 to n, inclusive, is a multiple of 990. What is least possible value of n? a) 10 b) 11 c) 12 d) 13 e) 14 A lot of integer property questions can be solved using prime factorization. For questions involving divisibility, divisors, ...
- by shwetagoyal121
Sun May 29, 2016 11:27 pm- Forum: Problem Solving
- Topic: If n is a positive integer, and the product of all integers
- Replies: 6
- Views: 13138