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Where
First Term = 12
Difference = 4
Last Term = 96
As per the formula
a+(n-1)d
12+(n-1)4 = 96
(n-1)4 = 96-12
(n-1)4 = 84
n-1 = 84/4
n-1 = 21
n=22
12 + (
- by vinokayal
Thu Sep 26, 2013 7:57 am- Forum: Problem Solving
- Topic: Multiples of 4 between 12 and 96
- Replies: 8
- Views: 11539