Search found 11 matches
If it is asking for what is the hundredths digit of decimal z, isn't z just a digit between 0-9? In that case, isn't isn't any other digit besides the units digit of z=0? e.g. z= 09.00? Let's assume z=9 1) 100z = 900.00; tenths digit = 0 2) 1000z = 9000.00; units digit = 0 D both alone are sufficient.
- by meh
Sun Jan 12, 2014 6:07 am- Forum: Data Sufficiency
- Topic: GMAT prep decimal
- Replies: 12
- Views: 8150
Ratios
If all variables are positive, is (w/x) > (y/z)? 1) w = y + 50 2) x = z + 50 1) and 2) alone are INS. (y+50)/(z+50) > y/z yz +50z > yz +50y 50y > 50z y > z Both together are INSUFICIENT so E) My question is, however: The first time that I worked it out, I simply did this... If w = y + 50 , then w > ...
Exponent Problem
If x is an integer, is 16^x + 16^-x = b
(1) 4^x + 4^-x = √(b+2)
(2) x>0
I know that the answer is A. But my question is, why, when you square on both sides doesn't √(b+2) end up being |b+2|?
- by meh
Sun Jan 05, 2014 12:07 pm- Forum: GMAT Math
- Topic: Exponent Problem
- Replies: 2
- Views: 1914
quadratic inequalities
4 - (x^2) ≥ 0 Way to do it... -1( (x^2) - 4 ) ≥ 0 (x^2) - 4 ≤ 0 x^2 ≤ 4 |x| ≤ 2 -2 ≤ x ≤ 2 One question: 1) If this is the best way to do it...why ever factor to make (x-2)(x+2) in any problem (inequality or not)? Doesn't the GMAT warn against directly solving for x in quadratics witho...
- by meh
Mon Dec 23, 2013 1:57 am- Forum: Data Sufficiency
- Topic: quadratic inequalities
- Replies: 1
- Views: 932
The "greater" ratio
What does it mean to be a "greater" ratio? I could see it as two ways: 1) the greater number when the ratio is put in fraction form or 2)the ratio with the greatest difference between numbers If P1 and P2 are the particles and R1 and R2 are the numbers of radioactive particles in Reactor 1...
- by meh
Thu Dec 19, 2013 10:41 am- Forum: Problem Solving
- Topic: The "greater" ratio
- Replies: 1
- Views: 1091
Estimating Percents. Please help :(
Hi there, I am having major difficulties estimating percents QUICKLY. My difficulty is that, it is impossible to know which method to use without applying it first, and even once you apply it, even the 10's digit may be wrong! Take 47/58. Method 1: 5/6 = about 83% Method 2: 46/58 = 23/29 = about (23...
- by meh
Mon Dec 16, 2013 6:28 am- Forum: Problem Solving
- Topic: Estimating Percents. Please help :(
- Replies: 1
- Views: 1028
Sure - based on the original question, both the lean and the fatty could be 8% That would be true, but one is noted as "lean ground beef" and the other "fatty ground beef" so we assume that fatty ground beef has a higher fat content. If this is the case, what other combination c...
- by meh
Mon Dec 16, 2013 5:54 am- Forum: Problem Solving
- Topic: weighted averages
- Replies: 8
- Views: 1902
- by meh
Fri Dec 13, 2013 12:12 pm- Forum: Problem Solving
- Topic: weighted averages
- Replies: 8
- Views: 1902
No, but I did alter the question. The original doesn't mention the amount of grams. It looks something like this... A mixture of lean ground beef with 2% fat is mixed with fatty ground beef with 10% fat to create a ground beef mix with 8% fat. What is the ratio of lean ground to to fatty ground beef...
- by meh
Fri Dec 13, 2013 12:12 pm- Forum: Problem Solving
- Topic: weighted averages
- Replies: 8
- Views: 1902
No, but I did alter the question. The original doesn't mention the amount of grams. It looks something like this... A mixture of lean ground beef with 2% fat is mixed with fatty ground beef with 10% fat to create a ground beef mix with 8% fat. What is the ratio of lean ground to to fatty ground beef...
- by meh
Fri Dec 13, 2013 12:11 pm- Forum: Problem Solving
- Topic: weighted averages
- Replies: 8
- Views: 1902
weighted averages
A mixture of 20 grams of lean ground beef is mixed with 50 grams of fatty ground beef to create a ground beef mix with 8% fat. How many grams of fat does the lean ground beef have? My method: 20 grams lean : 50 grams fatty : 70 grams total x% fat : y% fat : 10% fat (2 x (-diff) ) x (5 x (+diff) ) = ...
- by meh
Fri Dec 13, 2013 11:19 am- Forum: Problem Solving
- Topic: weighted averages
- Replies: 8
- Views: 1902