Search found 13 matches
arrangement
94. Find the numbers of ways in which 4 boys and 4 girls can be seated alternatively.
1) in a row and there is a boy named John and a girl named Susan amongst the group who cannot be put in adjacent seats
Pls help with explanation.
- by gupta.amit3
Sun Nov 09, 2008 8:41 am- Forum: Problem Solving
- Topic: arrangement
- Replies: 12
- Views: 2775
tough math problem - measurement
Two measure standards R and S. 24 and 30 measured with R are 42 and 60 when they are measured with S, respectively. If 100 is acquired with S, what would its value be measured with R?
Can somebody help with explanation.
- by gupta.amit3
Sun Nov 09, 2008 8:41 am- Forum: Problem Solving
- Topic: tough math problem - measurement
- Replies: 9
- Views: 4399
- by gupta.amit3
Sun Nov 09, 2008 8:39 am- Forum: Data Sufficiency
- Topic: GMAT Prep
- Replies: 2
- Views: 1594
- by gupta.amit3
Sun Nov 09, 2008 8:36 am- Forum: Data Sufficiency
- Topic: if x is prime?
- Replies: 4
- Views: 1494
| x – 3 | = | 3x + 2 | – 1 The modulus mentioned in equations will change signs at x=3 and x=-2/3 First consider x<-2/3 -(x-3) = -(3x+2) - 1 Solving, x=-3 Putting it back in the modulus equ you will find that both sides are equal to 6, so x=-3 is one solution consider -2/3<x<3 -(x-3) = (3x+2) - 1 So...
- by gupta.amit3
Wed Oct 08, 2008 9:36 am- Forum: Problem Solving
- Topic: General question with Absolute values
- Replies: 3
- Views: 1634
(1/5)^m(1/4)^18 = 1/2(10)^35 can be written as:
5^(-m)2^(-36) = 2^(-1)(2X5)^(-35) = 2^(-1-35)5^(-35)
Equating exponents on each side
-m=-35
Hence m=35 is ANS
- by gupta.amit3
Wed Oct 08, 2008 9:23 am- Forum: Problem Solving
- Topic: stumped on exponent problem
- Replies: 4
- Views: 1467
(1/5)^m(1/4)^18 = 1/2(10)^35 can be written as:
5^(-m)2^(-36) = 2^(-1)(2X5)^(-35) = 2^(-1-35)5^(-35)
Equating exponents on each side
-m=-35
Hence m=35 is ANS
- by gupta.amit3
Wed Oct 08, 2008 9:22 am- Forum: Problem Solving
- Topic: stumped on exponent problem
- Replies: 4
- Views: 1467
Subject/Verb Inversion
I am referring to Sumit's notes "APPENDIX B. Subject/Verb Inversion". The notes mention about 18 rules but I am not sure how to apply these rules. It will be really nice if some experts in this forum can help on these rules.
- by gupta.amit3
Wed Oct 08, 2008 9:13 am- Forum: Sentence Correction
- Topic: Subject/Verb Inversion types - Pls Help
- Replies: 2
- Views: 2023
Subject/Verb Inversion types - Pls Help
I have come across 18 Subject/Verb Inversion types in various study materials on internet but I am not able to fully apprehend the concept. Can somebody explain how to use these techniques for SC. I tried searching the forum but could not find the relevant thread. Pls help. 
:
- by gupta.amit3
Sun Oct 05, 2008 5:09 am- Forum: Sentence Correction
- Topic: Subject/Verb Inversion types - Pls Help
- Replies: 2
- Views: 2023
- by gupta.amit3
Sun Jul 27, 2008 10:38 pm- Forum: Lounge
- Topic: Free math questions- volunteers wanted
- Replies: 13
- Views: 4805
need help on Number Theory and Probability
I am planning to give GMAT around end Aug. In Quant section, I am doing good and I am able to answer more 90% of the questions correctly. After analysing my wrong answers I have come to conclusion that most of my problems are in the area of Probability or Number Systems. Pls help me in terms of guid...
- by gupta.amit3
Fri Jul 25, 2008 4:48 am- Forum: GMAT Math
- Topic: need help on Number Theory and Probability
- Replies: 2
- Views: 2208
- by gupta.amit3
Tue Jul 22, 2008 6:21 am- Forum: Problem Solving
- Topic: P and C
- Replies: 7
- Views: 2156
Not sure if I have understood the question completely. As per my understanding of the question "we are looking to see the possible combinations of 4 letters from the word"ENTRANCE". So ENTRANCE has 6 unique letters. So the ANS should be 6C4=6C2=15 But I don't see this in answer choice...
- by gupta.amit3
Tue Jul 22, 2008 6:03 am- Forum: Problem Solving
- Topic: Permutaion & combination
- Replies: 7
- Views: 5428