Profile evaluation request

Hello, First of all, thanks to all of the admission consultants who take the time to post on this forum...you provide some great information on the process! I'm a 26-year-old male looking to apply to b-school this fall for entry to a full time program in the fall of '09. A little about my background...

I believe its A...p-1. If a number is prime, its only factors are 1 and itself. Therefore, if p is a prime, any number less p will not be a factor of p. So, each of the p-1 integers less than p will have no factor in common with p other than 1, which implies that f(p) = p-1. As an example, consider ...

Statement (1) tells us that x is an odd number (has remainder of 1 when divided by 2) and that x is divisible by 3. If you list out the odd multiples of 3 you will see that they all have a remainder of 3 when divided by 6... 3,9,15,21,27,..... Therefore, we know that x will have a remainder of 3 whe...

width of picture = x length of picture = 2x width of picture+border = x+4 (2 inches on each end) length of picture+border = 2x+4 (2 inches on each end) If you draw this out it will be easier to visualize, but the area of the border alone is given as 196. This is also equal to the area of the picture...

When you raise a number to a negative exponent, it is equivalent to taking the recirpocal of the number and raising it to the opposite of the negative exponent. In other words... 2^(-3) = 1/(2^3) = 1/8. Using this, (3^-(x+y))/(3^-(x-y)) can be written as (3^(x-y))/(3^(x+y)) When different powers of ...

Not sure there is really a shortcut...at least I don't see one immediately. You could factor out 5^12, giving you (5^12)(1+5+25) = 31(5^12) Then, I expressed 5^12 = 25^6 = 625^3. From there I multiplied out 625*625*625 and multiplied the result by 31. This does take a minute or two to do by hand, so...

I think this one is B - X^3=27. As you go through the inequalities, think about which values of x will satisfy them and then imagine plotting these x values on a number line. X^4>1...for this equation, raising a negative number to an even power will make the number positive. For example, (-2)^4 = 16...

I'd say it's A - I Only. From the question, we know that the sum of the 15 prices must be $2,250,000 and that 8th price (when prices arranged from lowest to highest) must be $130,000. So, the first 7 prices must all be less than or equal to $130,000. Statement I - the most money we can get out of th...