Search found 94 matches
Just got beaten down to pulp by GMAT
Scored 580. Disappointed to the core. I was quite sure I'd at least manage a score of 650. I don't know what happened. In all my mocks I was doing great in my verbal. But somehow goofed up on the D-day. (Score: Q 44; V 26).
- by cypherskull
Thu Aug 30, 2012 10:51 pm- Forum: I just Beat The GMAT!
- Topic: Just got beaten down to pulp by GMAT
- Replies: 2
- Views: 1560
- by cypherskull
Tue Aug 28, 2012 9:35 am- Forum: GMAT Strategy
- Topic: D-day tomorrow
- Replies: 5
- Views: 1473
I wish I'd seen the video about timing strategies before and practiced with my mock exams. Its great!!! I hope I can put it to use tomorrow. And thanks a lot Brent for sharing the link!
- by cypherskull
Tue Aug 28, 2012 7:24 am- Forum: GMAT Strategy
- Topic: D-day tomorrow
- Replies: 5
- Views: 1473
- by cypherskull
Tue Aug 28, 2012 6:45 am- Forum: Problem Solving
- Topic: Counting and probability
- Replies: 8
- Views: 1535
Thanks a lot Brent! I understood both the approaches you explained. But I'm not sure where I went wrong in my approach. Here's how I selected the number of ways to choose non-pairs - 1st card - 12 ways 2nd card - 10 ways (since 11 cards remaining one of which has the same value as the 1st card) Simi...
- by cypherskull
Tue Aug 28, 2012 6:20 am- Forum: Problem Solving
- Topic: Counting and probability
- Replies: 8
- Views: 1535
- by cypherskull
Tue Aug 28, 2012 4:35 am- Forum: GMAT Strategy
- Topic: D-day tomorrow
- Replies: 5
- Views: 1473
- by cypherskull
Tue Aug 28, 2012 2:54 am- Forum: Problem Solving
- Topic: Number of squares
- Replies: 3
- Views: 859
Number of squares
A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an area of 100. If all coordinates of the vertices must be integers, how many different ways can this square be drawn?
a.4
b.6
c.8
d.10
e.12
- by cypherskull
Tue Aug 28, 2012 2:35 am- Forum: Problem Solving
- Topic: Number of squares
- Replies: 3
- Views: 859
You're right by all means. And that's precisely my question here too. I first tried 12C4. Got an incorrect answer. While doing a hit n trial, I observed that 12P4 worked. That's my question...HOW and WHY did it work? I researched a little further and it turns out that my numerator (12*10*8*6) is inc...
- by cypherskull
Tue Aug 28, 2012 1:58 am- Forum: Problem Solving
- Topic: Counting and probability
- Replies: 8
- Views: 1535
- by cypherskull
Tue Aug 28, 2012 1:53 am- Forum: Data Sufficiency
- Topic: x>y?
- Replies: 1
- Views: 771
Counting and probability
Bill has a small deck of 12 playing cards made up of only 2 suits of 6 cards each. Each of the 6 cards within a suit has a different value from 1 to 6; thus, for each value from 1 to 6, there are two cards in the deck with that value. Bill likes to play a game in which he shuffles the deck, turns ov...
- by cypherskull
Tue Aug 28, 2012 12:24 am- Forum: Problem Solving
- Topic: Counting and probability
- Replies: 8
- Views: 1535
Given x is an interger From Statement (1) [x + y + (y-2)]/3 = x => x + 2y - 2 = 3x => 2y - 2 = 2x => y - 1 = x => y = x + 1 => Since x is an integer, x + 1 (=y) will also be an integer [Sufficient] From statement (2) (x + y)/2 => not an integer. Here y can take on both integer as well as non-integer...
- by cypherskull
Mon Aug 27, 2012 11:05 pm- Forum: Data Sufficiency
- Topic: y an integer?
- Replies: 2
- Views: 933
Calculate the distance b/w (-2,-3) and (-2,1); d = 4.
Since (-2,1) is inside the circle, r > 4. Eliminate C,D,E.
Calculate the distance b/w (-2,-3) and (4,-3); d = 6.
Since (4,-3) is outside the circle, r < 6. Eliminate A. [spoiler]Ans:B[/spoiler]
- by cypherskull
Mon Aug 27, 2012 12:26 pm- Forum: Problem Solving
- Topic: Circles...Radius problem...??
- Replies: 3
- Views: 868
Yep. I got the same thing. Both B & E are correct. Although, I learned an interesting technique of comparing fractions which saves me a lot of time I used to take in calculating decimal equivalents. Sharing it just in case anyone finds it useful. Considering the 2 fractions - 2/3 (LHS) and 3/4 (...
- by cypherskull
Mon Aug 27, 2012 12:16 pm- Forum: Problem Solving
- Topic: Number between 2/3 and 3/4
- Replies: 5
- Views: 5175
sqrt[4(4*20 + 2*32)]To solve, I pulled out the greatest common factor, 4.
= sqrt[4((4*5) + (2*8))]
= 2 * sqrt (20+16)
= 2 * sqrt (36)
= 2 * 6
= 12
= 2*sqrt[80 + 64]
= 2*sqrt[144]
= 2*12
= 24
See where u went wrong? You took an extra 4 out!
- by cypherskull
Mon Aug 27, 2012 10:53 am- Forum: Problem Solving
- Topic: Algebra Problem
- Replies: 3
- Views: 1031