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GMAT Strategy for Working Professionals

Hi All,
I work full time and looking for some motivation to study after stressful work day.
I wonder if there is any strategy defined for Working Professionals. Please share it in this Topic.


Thanks,
Everest

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GMATgroup Milpitas+Santaclara+ Sunnyvale+San jose+Cupertino

Hi All,
I work fulltime and looking for a serious study groups in bay area, california.
Please message me and will take it from there.

Milpitas
Santaclara
Sunnyvale
San jose
Cupertino
Campbell
Mountain view

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let's define the set = -4, -3, -2, -1, 0, 1 , 2 ,3, 4, 5, 6, 7 (12 integers)

Number of positive integers are = 1 , 2 ,3, 4, 5, 6, 7 (0 is neither positive not negative)


Range = max - min = 7 -1 = 6

IMO B

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The first place has 9 possibilities, since 0 is not counted.
All others have 9 possibilities each, since you cannot have the digit similar to the previous one.

9 * 9 * 9 * 9 * 9 = 9^5

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Night reader wrote:

SFtraveler wrote:Please show each step in factoring: 5^k-5^(k-1)

5^k -5^(k-1) = 5^k(1 - 1*(-1/5)) = 6*5^k/5

Not sure how 5^k -5^(k-1) becomes 5^k(1 - 1*(-1/5))

It should be 5 ^k - 5^k/5 = 5^k(1-1/5) = 4/5 * 5^k or 4 * 5^k-1

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5^k-5^(k-1) => 5^K - 5^k * 5^ -1 = 5^k (1 - 1/5) = 5^K * 4/5 = 4 (5^(k-1))

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An integer has exactly 3 divisors if and only if it is the square of a prime number. Below are the prime numbers which when squared result less than 900. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29 There are 10 integers which have exactly 3 positive divisors. I think this is incorrect. 2^2 =4 the positive d...

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If n is a prime number greater than 3, what is the
remainder when n^2 is divided by 12 ?


Easy method is substitution of primes greater than 3.

5 is a prime number greater than 3

5^2 = 25 , when 25 is divided by 12 remainder is 1.