Search found 21 matches
Sec 4, #25
25. Pam and Ed are in a line to purchase tickets. How many people are in the line? (1) There are 20 people behind Pam and 20 people in front of Ed. (2) There are 5 people between Pam and Ed. --- I set it up as: 20, E, 5, P, 20 = 47 b/c there are 5 people b/w P and E, it can't be P then E. but OA is E
- by cindyqtran
Mon Oct 29, 2007 8:43 pm- Forum: Data Sufficiency
- Topic: Sec 4, #25
- Replies: 1
- Views: 1554
- by cindyqtran
Mon Oct 29, 2007 7:09 pm- Forum: Data Sufficiency
- Topic: Sec 3, #25
- Replies: 1
- Views: 1673
sec 3, #20
20. In the figure above, line AC represents a seesaw that is touching level ground at point A. If B is the midpoint of AC, how far above the ground is point C?
(1) x = 30
(2) Point B is 5 feet above the ground.
OA is B
- by cindyqtran
Mon Oct 29, 2007 6:50 pm- Forum: Data Sufficiency
- Topic: sec 3, #20
- Replies: 1
- Views: 1639
Section 2 #25
25. If x and y are consecutive odd integers, what is the sum of x and y?
(1) The product of x and y is negative.
(2) One of the integers is equal to –1.
OA is A
- by cindyqtran
Mon Oct 29, 2007 4:28 pm- Forum: Data Sufficiency
- Topic: Section 2 #25
- Replies: 1
- Views: 1229
- by cindyqtran
Sat Sep 29, 2007 12:14 pm- Forum: Problem Solving
- Topic: PS1000 Set 23, #20
- Replies: 2
- Views: 1625
- by cindyqtran
Sat Sep 29, 2007 10:21 am- Forum: Problem Solving
- Topic: PS1000 Set 23, #20
- Replies: 2
- Views: 1625
- by cindyqtran
Tue Sep 25, 2007 10:05 pm- Forum: Problem Solving
- Topic: PS1000, Set 8, 20
- Replies: 1
- Views: 1728
PS1000, Set 7, 19
The sum of the first 100 positive integers is 5,050. What is the sum of the first 200 positive integers?
(A) 10,100
(B) 10,200
(C) 15,050
(D) 20,050
(E) 20,100
- by cindyqtran
Mon Sep 24, 2007 10:10 pm- Forum: Problem Solving
- Topic: PS1000, Set 7, 19
- Replies: 4
- Views: 1788
- by cindyqtran
Sun Sep 23, 2007 6:21 pm- Forum: Problem Solving
- Topic: Set 15 Q 26
- Replies: 6
- Views: 2000
is the answer D?
A. 16x where x can be: 1/2, 1/4, 1/8 (SUFF. .5, .25, .125)
B. 8x where x can be 1/2, 1/4 (SUFF. .5, .25...)
- by cindyqtran
Sun Sep 23, 2007 3:57 pm- Forum: Problem Solving
- Topic: Set 15 Q 26
- Replies: 6
- Views: 2000
- by cindyqtran
Sun Sep 23, 2007 3:44 pm- Forum: Problem Solving
- Topic: 1000PS Section 3 Qusetion 20
- Replies: 2
- Views: 4958
- by cindyqtran
Sun Sep 23, 2007 9:33 am- Forum: Problem Solving
- Topic: GMAT Prep
- Replies: 4
- Views: 1731
is the answer B?
since we know that one of the side is 1, so the largest length of the other side is 1. so A = 0.5bh = .5*1*1 = .5
- by cindyqtran
Sun Sep 23, 2007 9:09 am- Forum: Problem Solving
- Topic: GMAT Prep
- Replies: 2
- Views: 1586
hi.
are you sure the answer is C?
I would think it is E, because even though you have the ratios for each, answer B just states that the number of Women is less than 30 (i.e. 5, 10, 15, 20 , 25). Because this is not a constant value, we cannot determine the values of the others.
- by cindyqtran
Sun Sep 23, 2007 8:59 am- Forum: Problem Solving
- Topic: GMAT Prep
- Replies: 4
- Views: 1731
hi.
.01x + .02y + .03z = 0.15(x+y+z)
x + 2y + 3z = 1.5(x + y+ z)
.5y + .15z = .5x
5y + 15z = 5x
x = y + 3z
- by cindyqtran
Sun Sep 23, 2007 8:54 am- Forum: Problem Solving
- Topic: GMAT Prep
- Replies: 2
- Views: 1504