If 0<x<y, what is the vale of [(x+2)^2] / [(x-2)^2]
1. x^2 + y^2 = 3xy
2. xy = 3
Value of (GMAT prep)
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(x + y)²/(x - y)² = (x² + 2xy + y²)/(x² - 2xy + y²)alex.gellatly wrote:If 0<x<y, what is the vale of [(x+2)^2] / [(x-2)^2]
1. x^2 + y^2 = 3xy
2. xy = 3
Statement 1: (x² + y²) = 3xy
Hence, (x² + 2xy + y²)/(x² - 2xy + y²) = (3xy + 2xy)/(3xy - 2xy) = (5xy)/(xy) = 5
Sufficient
Statement 2: xy = 3
This is not enough to answer the question.
Not sufficient
The correct answer is A.
Anurag Mairal, Ph.D., MBA
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