Rates and Distance

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Rates and Distance

by singhmaharaj » Tue May 06, 2014 5:05 am
On his trip from Alba to Benton, Julio drove the first x miles at an average rate of 50 miles per hour and the remaining distance at an average rate of 60 miles per hour. How long did it take Julio to drive the first x miles?

1) On the trip, Julio drove for a total of 10 hours and drove a total of 530 miles.

2) On his trip, it tool Julio 4 more hours to drive the first x miles than to drive the remaining distance.

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by GMATGuruNY » Tue May 06, 2014 6:54 am
singhmaharaj wrote:On his trip from Alba to Benton, Julio drove the first x miles at an average rate of 50 miles per hour and the remaining distance at an average rate of 60 miles per hour. How long did it take Julio to drive the first x miles?

1) On the trip, Julio drove for a total of 10 hours and drove a total of 530 miles.

2) On his trip, it took Julio 4 more hours to drive the first x miles than to drive the remaining distance.
Statement 2: On his trip, it took Julio 4 more hours to drive the first x miles than to drive the remaining distance.
It's possible that julio took 5 hours to travel the first x miles and 1 hour to travel the remaining distance.
It's possible that Julio took 10 hours to travel the first x miles and 6 hours to travel the remaining distance.
Since the time to travel the first x miles can be different values, INSUFFICIENT.

Statement 1: On the trip, Julio drove for a total of 10 hours and drove a total of 530 miles.
Average speed for the whole trip = d/t = 530/10 = 53 miles per hour.

This is a MIXTURE problem.
Two speeds (50mph and 60mph) are combined to form a mixture with an average speed of 53mph.
To determine how much time must be spent at each speed, we can use ALLIGATION.
Let S = the slower speed and F = the faster speed.

Step 1: Plot the 3 speeds on a number line, with F and S on the ends and the speed for the mixture (53mph) in the middle.
S 50---------53----------60 F

Step 2: Calculate the distances between the values on the number line.
S 50----3----53----7-----60 F

Step 3: Determine the ratio of the two given speeds.
The ratio of S to F is the RECIPROCAL of the distances in red.
S:F = 7:3.

Implication:
Of the 10 hours of travel time, 7 hours are traveled at 50mph and 3 hours are traveled at 60mph.
Thus, Julio spent 7 hours traveling the first x miles at 50mph.
SUFFICIENT.

The correct answer is A.

Please note the following:
Almost NO MATH is needed for statement 2 if we understand how WEIGHTED AVERAGES work.
Given a SLOWER SPEED, a FASTER SPEED, and an AVERAGE SPEED, we can always determine the required TIME RATIO for the slower speed and the faster speed.
In general:
If part of a trip is traveled at x mph, the rest of the trip is traveled at y mph, and the average speed for the whole trip is z mph, the following ratio can be determined:
(time spent traveling at x mph)/(time spent traveling at y mph).

Other alligation problems:
https://www.beatthegmat.com/mixture-prob ... tml#593241
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by [email protected] » Tue May 06, 2014 11:50 am
Hi singhmaharaj,

This DS question is built around an interesting shortcut that most people miss.

We're told that Julio drove part of a trip (the first X miles) at 50mph and the other part of the trip (everything after the first X miles) at 60mph. This means that the overall average speed will be some speed between 50mph and 60mph. We're asked how long it took to drive the first X miles.

In Fact 1, we're told that the entire trip took 10 hours and the total distance was 530 miles.

As Mitch noted, this is a mixture question. His explanation shows you how to solve the mixture, but you don't technically have to do that work in this question.

With a total of 10 hours....

If the entire trip was at 50mph, then the total distance would be 500 miles
If the entire trip was at 60mph, then the total distance would be 600 miles

As you "take time away" from 60mph and "add time" to 50mph, the total distance decreases from 600 miles on down.

eg. 9 hours at 60mph and 1 hour at 50mph = 590 miles
8 hours at 60mph and 2 hours at 50mph = 580 miles
etc.

This means that there will be exactly ONE combination that = 530 miles exactly. The cool part is that we don't even need to figure it out; we KNOW there's just one possibility. With that limitation, we would know how much time was spent driving each speed, so we could answer the given question.

Thus, Fact 1 is SUFFICIENT.

Fact 2 is fairly easy to deal with since it does not give us enough info to determine the exact amount of time that the first X miles took.

Final Answer: A

Many DS question are built around interesting "hidden" shortcuts. Practice looking for these patterns and you'll find that you can answer many of these questions quicker than you originally realize.

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