There are 11 women and 9 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?
A. 120
B. 720
C. 1,060
D. 1,520
E. 1,980
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GMATPrep CAT (Taken Feb 28, 09): 590 (Q-39, V-34)
Manhattan GMAT Adaptive CAT (Taken March 6, 09): 640 (Q-44, V-34)
800Score CAT (Taken March 14, 09): 630 (Q-41, V-36)
800score CAT (Taken March 20, 09): 600 (Q-41, V-31)
Manhattan GMAT Adaptive CAT (Taken March 22, 09): 600 (Q-39, V-34)
GMATPrep CAT (Taken March 28, 09): 570 (Q-37, V-31)
Knewton Diagnostic CAT (Taken April 3, 09): 640 (Q-45, V-33)
There are a total of 11!/2!(11-2)! * 9!/2!(9-2)! = 1980jkwan wrote:There are 11 women and 9 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?
A. 120
B. 720
C. 1,060
D. 1,520
E. 1,980
11!/2!9! = 11*10*9!/2!9!=11*10/2
9!/2!7!=9*8*7!/2!7!=9*8/2
55*36=1980
I think this is right~
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gaggleofgirls
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The number of possible committees = number of ways to chose 2 from the 11 women * number of possible ways to chose 2 from the 9 men.
11c2 * 9c2
(11! / 2!*9!) * (9! / 2!*7!)
(11*10 / 2) * (9*8/2)
(11*5) * (9*4)
55 *36
1980
Answer = E
-Carrie
11c2 * 9c2
(11! / 2!*9!) * (9! / 2!*7!)
(11*10 / 2) * (9*8/2)
(11*5) * (9*4)
55 *36
1980
Answer = E
-Carrie
GMAT/MBA Expert
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Scott@TargetTestPrep
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We need to determine how many different committees are possible with 2 women and 2 men from 11 women and 9 men. Let's first determine the number of ways to select 2 women.jkwan wrote:There are 11 women and 9 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?
A. 120
B. 720
C. 1,060
D. 1,520
E. 1,980
number of ways to select 2 women from 11 of them = 11C2 = (11 x 10)/2! = 55 ways
Next we determine the number of ways to select 2 men.
number of ways to select 2 men from 9 of them = 9C2 = (9 x 8)/2! = 36 ways
Thus, the number of ways to select 2 women and 2 men is 55 x 36 = 1,980 ways.
Answer: E
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