R, S, & T all have the same remainder when divided by 5.

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Interested to see how you solve this one. I thought the answer was E, but it's not.

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by theCodeToGMAT » Thu Sep 26, 2013 10:56 am
Answer [spoiler]{C}[/spoiler]
r = 5A + R
s = 5B + R
t = 5C + R

Statement 1:
5A + R + 5B + R = 5C + R
2R = R (since 5A,5B & 5C are divisible by 5.. so removing)
R = 0
That means t is 5 Multiple.. but we dont know which value..
INSUFFICIENT

Statement 2:
no info of r and s so "t" can take any value..
INSUFFICIENT

Combining....
20
R A H U L

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by GMATGuruNY » Thu Sep 26, 2013 1:07 pm
fourteenstix wrote:Image
Since r, s, and t all have a remainder of R when divided by 5, they must ALL be contained in ONE of the following lists:
Case 1: R=0
0, 5, 10, 15, 20, 25...
Case 2: R=1
1, 6, 11, 16, 21, 26...
Case 3: R=2
2, 7, 12, 17, 22, 27...
Case 4: R=3
3, 8, 13, 18, 23, 28...
Case 5: R=4
4, 9, 14, 19, 24, 29...

Statement 1: r+s = t
Only Case 1 is viable.
No combination of values from the remaining cases will satisfy the constraint that r+s = t.
In Case 1, it's possible that r=5. s=5, and t=10.
In Case 1, it's possible that r=5, s=10, and t=15.
Since t can take on different values, INSUFFICIENT.

Statement 2: 20 ≤ t ≤ 24
In Case 1, it's possible that t=20.
In Case 2, it's possible that t=21.
Since t can take on different values, INSUFFICIENT.

Statements combined:
Only one value in Case 1 satisfies the constraint that t is between 20 and 24, inclusive: t=20.
SUFFICIENT.

The correct answer is C.
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by Java_85 » Fri Sep 27, 2013 1:14 pm
IMO C is the answer.