Question

There are six cards bearing numbers 2,4,5,5,5,6. If two cards are randomly selected from the lot, what is the probability that the difference between the numbers on these cards is 3 or less?

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shankar.ashwin: Legendary Member; Posts: 966; Joined: Sat Jan 02, 2010 8:06 am; Thanked: 230 times; Followed by:21 members

by shankar.ashwin » Wed Nov 09, 2011 1:09 am

Possibilities that give you a difference of more than 3.

6-2 = 4

Total possibilities - 6C2 = 15.

All other combinations will have a difference of 3 or less.

So, (15-1)/15 = 14/15 IMO

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[email protected]: Junior | Next Rank: 30 Posts; Posts: 26; Joined: Sat Aug 27, 2011 8:50 pm

by [email protected] » Mon Jan 16, 2012 10:57 am

Total Possibilities = 6C2 = 15

Possibilities that will give difference of 3 or less = 1- Possibility of more than 3.

Possibility of getting difference more than 3 = 6-2. only 1.

Required probability = 1 - 1/15 = 14/15 IMO.

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LalaB: Master | Next Rank: 500 Posts; Posts: 425; Joined: Wed Dec 08, 2010 9:00 am; Thanked: 56 times; Followed by:7 members; GMAT Score:690

by LalaB » Tue Jan 17, 2012 12:41 am

do not u think that there should be noted,that the difference must be non negative?
IMHO, the q is ambiguous

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