OG GUide quantitative (Green book)Data Sufficiency: question #113
In the fraction x/y, where, x and y both positive integers, what is value of Y.
1.) least common denominator of x/y and 1/3 is 6.
2.) x=1.
question # 114. Data Sufficiency
IS 1/a-b < b-a?
1.)a<b
2.) y>2
both tough for me and i think I am making the questions harder than they are!
question for d.s.
This topic has expert replies
113. In the fraction x/y, where, x and y both positive integers, what is value of Y.
1.) least common denominator of x/y and 1/3 is 6.
Y can have two values 2 and 6 for which least common denominator can be 6. e.g. (7/6 and 1/3) & (7/2 and 1/3)
NOT SUFFICIENT.
2.) x=1.
This doesn't give any value for Y.
NOT SUFFICIENT.
(1) & (2) together:
Y can have two values 2 and 6 for which least common denominator can be 6.
e.g. (1/6 and 1/3) & (1/2 and 1/3)
NOT SUFFICIENT.
Answer E.
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114. Is 1/a-b < b-a?
1.)a < b
(b-a) will be positive.
(a-b) will be negative.
This follows that b-a(+ve) will be greater than 1/(a-b) {-ve}
SUFFICIENT.
2.) y>2
Equation uses variable y, which is not used in the equation, NOT SUFFICIENT.
I guess it should be either a > 2 or b > 2.
1.) least common denominator of x/y and 1/3 is 6.
Y can have two values 2 and 6 for which least common denominator can be 6. e.g. (7/6 and 1/3) & (7/2 and 1/3)
NOT SUFFICIENT.
2.) x=1.
This doesn't give any value for Y.
NOT SUFFICIENT.
(1) & (2) together:
Y can have two values 2 and 6 for which least common denominator can be 6.
e.g. (1/6 and 1/3) & (1/2 and 1/3)
NOT SUFFICIENT.
Answer E.
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114. Is 1/a-b < b-a?
1.)a < b
(b-a) will be positive.
(a-b) will be negative.
This follows that b-a(+ve) will be greater than 1/(a-b) {-ve}
SUFFICIENT.
2.) y>2
Equation uses variable y, which is not used in the equation, NOT SUFFICIENT.
I guess it should be either a > 2 or b > 2.