PS practice problems

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by givemeanid » Sun Jul 15, 2007 7:11 am
n = (2 * 3 * 5 * 7 * 11 * 13) / 77k
= 2*3*5*13/k

For n to be an integer, k has to be a factor of 2*3*5*13

(A) 22 = 2*11. NO
(B) 26 = 2*13. YES
(C) 35 = 5*7. NO
(D) 54 = 2*3*3*3. NO
(E) 60 = 2*2*3*5. NO

Answer is B.
So It Goes