Hi, I been having problems with these types of questions lately. Anyone fancy giving me a few tips and approach strategy?
"If n is a positive internet, and the product of all integers from 1 to n is a multiple of 990, what is the lowest possible integer for n?
a.10
b.11
c.12
d.13
e.14
b
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Product of all Numbers type of Question
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Rahul@gurome
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990 = 11*10*9 = 2*3²*5*11bkk_marc wrote:If n is a positive internet, and the product of all integers from 1 to n is a multiple of 990, what is the lowest possible integer for n?
a.10
b.11
c.12
d.13
e.14
b
Therefore n must be such that the product of all integers from 1 to n must contain largest prime factor of 990, i.e. 11. Thus minimum value of n is 11.
The correct answer is B.
Rahul Lakhani
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Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
