Can you help me tackle the following problem?
A bowl of fruit contains only apples, oranges, and pears. If a piece of fruit is randomly selected from the bowl, what is the probability that the piece of fruit is an apple?
(1) Half of the fruit in the bowl is oranges.
(2) The probability of selecting a pear is 30 percent.
Thank you in advance
probability
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Well if i apply a simple logic, seebek_gmat wrote:Can you help me tackle the following problem?
A bowl of fruit contains only apples, oranges, and pears. If a piece of fruit is randomly selected from the bowl, what is the probability that the piece of fruit is an apple?
(1) Half of the fruit in the bowl is oranges.
(2) The probability of selecting a pear is 30 percent.
Thank you in advance
the probability of selecting an apple = 1 - (prb of orange + prb of pear)
So in my opinion, Op C is the answer.
What's the correct answer!!!
- amit2k9
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yupp
a+b we have,
1- (0.5+0.3) = 0.2 or 20%
a+b we have,
1- (0.5+0.3) = 0.2 or 20%
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