252 toys of same type are to be given to 'c' number of children, such that 1<=c<=252. Each child should get an equal number of toys. How many values can 'c' take ?
A) 16
B) 17
C) 18
D) 19
E) 20
Well my approach was to factorize 252= 2*2*3*3*7
Then i realised that c can take multiple values such as 2,3,7,6,14 but then i got lost in the process
Plz help
OA:c
Factorization
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252= 2*2*3*3*7
or 252= 2^2*3^2*7
So total number of factors of 252,including 1 and 252 is (2+1)*(2+1)*(1+1)=18
hence number of values of C can be 18
Ans option C
or 252= 2^2*3^2*7
So total number of factors of 252,including 1 and 252 is (2+1)*(2+1)*(1+1)=18
hence number of values of C can be 18
Ans option C
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My gmat approach
(One should always bear that gmat approach and normal approach are completely different things)
it should be divided among equal person
so what ever gives 0 remainder is answer here
and while guessing always start from C (lol....hope gmac people are not watching ...)
so 252/18 .....wow....no remainder ...i work as 180+90-18.....i dont remember table of 18
so done...C
i dont bother to check others....
if there are other such option with remainder 0 then question is wrong....
but question writer are cleaver....
they will say ...max value c can take....
then it will require some more work...
(One should always bear that gmat approach and normal approach are completely different things)
it should be divided among equal person
so what ever gives 0 remainder is answer here
and while guessing always start from C (lol....hope gmac people are not watching ...)
so 252/18 .....wow....no remainder ...i work as 180+90-18.....i dont remember table of 18
so done...C
i dont bother to check others....
if there are other such option with remainder 0 then question is wrong....
but question writer are cleaver....
they will say ...max value c can take....
then it will require some more work...
my approach:
goal is to calculate the number of combinations of numbers that will divide 252 into an integer
step 1: factor 252 into primes = 2^2*3^2*7
step 2: number of combinations of such numbers= 3 choices for 2 (zero 2s, one 2, or two 2s)*3 choices for 3 (zero 3s, one 3, or two 3s)*2 choices for 7 (zero 7s, or one seven)= 3*3*2=18
goal is to calculate the number of combinations of numbers that will divide 252 into an integer
step 1: factor 252 into primes = 2^2*3^2*7
step 2: number of combinations of such numbers= 3 choices for 2 (zero 2s, one 2, or two 2s)*3 choices for 3 (zero 3s, one 3, or two 3s)*2 choices for 7 (zero 7s, or one seven)= 3*3*2=18
Last edited by gmatjedi on Sun May 23, 2010 8:21 am, edited 1 time in total.
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Corrected ur typo error!!( look for bold letters)gmatjedi wrote:my approach:
goal is to calculate the number of combinations of numbers that will divide 252 into an integer
step 1: factor 252 into primes = 2^2*3^2*7
step 2: number of combinations of such numbers= 3 choices for 2 (zero 2s, one 2, or two 2s)*3 choices for 3 (zero 3s, one 3, or two 3s)*2 choices for 7 (zero 7s, or one seven)= 3*3*2=18
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IMO Cmitaliisrani wrote:252 toys of same type are to be given to 'c' number of children, such that 1<=c<=252. Each child should get an equal number of toys. How many values can 'c' take ?
A) 16
B) 17
C) 18
D) 19
E) 20
Well my approach was to factorize 252= 2*2*3*3*7
Then i realised that c can take multiple values such as 2,3,7,6,14 but then i got lost in the process
Plz help
OA:c
I followed the reverse approach i.e. dividing 252 from the given options