Problem Solving

Source- Veritas

What is the probability of getting exactly 2 sixes on three rolls of a fair six sided side?

Please verify my solution.

[spoiler]Possible Scenario 1 - Roll 1 - 6 ; Roll 2 - 6 ; Roll 3 - X (a number other than 6)

P(6) AND P(6) AND P (NOT 6)

1/6 * 1/6 * 5/6 = 5/216

No of ways to rearrange possible scenario 1 - Permutations with duplicates

3!/2! = 3

Therefore, 15/216[/spoiler]

jerryragland wrote:Source- Veritas

What is the probability of getting exactly 2 sixes on three rolls of a fair six sided side?

Please verify my solution.

[spoiler]Possible Scenario 1 - Roll 1 - 6 ; Roll 2 - 6 ; Roll 3 - X (a number other than 6)

P(6) AND P(6) AND P (NOT 6)

1/6 * 1/6 * 5/6 = 5/216

No of ways to rearrange possible scenario 1 - Permutations with duplicates

3!/2! = 3

Therefore, 15/216[/spoiler]

Write your answer in its lowest terms, rest is fine.