Hi,
By knowing that those two triangles are isoisoscales, how do we know the angle of X? Could anyone explain how to get the angle X?
Thank you!
powerprep #7
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- jayhawk2001
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1 tells us that angle(RSQ) = angle(SQR). Lets call this y.
Therefore angle(QRS) = 180 - 2y. In anycase, it is insufficient
2 tells us that angle (SUT) = angle (UST). Lets call this z.
Angle (STU) = 180 - 2z. Insufficient.
Combining 1 and 2,
x + y + z = 180 (3 angles together form the straight line).
Also, for triangle RPT, we have
90 + (180 - 2y) + (180 - 2z) = 180
y + z = 135
Subst y+z in the first equation, we can get x
Hence C
Therefore angle(QRS) = 180 - 2y. In anycase, it is insufficient
2 tells us that angle (SUT) = angle (UST). Lets call this z.
Angle (STU) = 180 - 2z. Insufficient.
Combining 1 and 2,
x + y + z = 180 (3 angles together form the straight line).
Also, for triangle RPT, we have
90 + (180 - 2y) + (180 - 2z) = 180
y + z = 135
Subst y+z in the first equation, we can get x
Hence C