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jtsgmat Just gettin' started!
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Posted: Tue Jul 18, 2006 5:22 am Post subject: Number Properties |
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Does anyone know how to solve this?
If P is a set of integers and 3 is in P, is evervy positive multipe of 3 in P?
1) For any integer in P, the sum of 3 and that integer is aslo in P.
2) For any integer in P, that integer minus 3 is also in P.
AD
BCE
Jason |
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lan0583 Just gettin' started!
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Posted: Tue Jul 18, 2006 5:31 am Post subject: |
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I believe that the answer is E. Here's how I got the answer.
A. INSUFFICIENT: 3+1=4 which is not a multiple of 3, however, 3+3 is multiple of 3.
B. INSUFFICIENT: 6-3= 3 which is a multiple of 3, however, 2-3 is not a multiple of 3.
D. CANNOT BE: Because if we combined the two statements, it does not say anything about the answer. It always comes down to having two or more different answers.
I dont know if I am right but that's how I analyzed the problem. |
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joedinan Just gettin' started!
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Posted: Fri Jul 21, 2006 8:36 pm Post subject: Re: Number Properties |
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| jtsgmat wrote: | Does anyone know how to solve this?
If P is a set of integers and 3 is in P, is evervy positive multipe of 3 in P?
1) For any integer in P, the sum of 3 and that integer is aslo in P.
2) For any integer in P, that integer minus 3 is also in P.
AD
BCE
Jason |
I see it as A
if you have 3 in the set, and for any integer in P you add 3, then you would have 3, (3+3), (6 +3), etc...
but that's just my take. |
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rehanaj Just gettin' started!
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Posted: Fri Jul 21, 2006 9:59 pm Post subject: |
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The answer could be A depending upon the interpretation of the problem.
In another interpretation of the problem, the answer could be (C).
I just took the set like {-3, 0 3}
I looked at statement (1)
-3 + 3 = 0 is in the set
0 + 3 is in the set
3 + 3 should be there as well, so set should be {-3, 0 , 3 , 6}
So you could go ad infinitum to show that the set is really {-3, 0, 3, 6, ...+infinity}
Sufficient
Then I looked at statement 2, Again started with {-3,0,3} backwards
3 - 3 = 0 is in the set
0 - 3 = -3 is in the set
-3 - 3 = -6 should also be there, so set should be {-6, -3, 0, 3}
So you could go ad infinitum to show that the set is really {-infinity, ...-3, 0, 3}
OK, so Statement 2 tells me that all positive multiples of 3 are not in P, UNLESS P already has ALL positive multiples of 3. That is, a situation like
{-infinity, ..., -3, 0, 3, 6, ....+infinity}
If that were not the case, I could argue that Statement 2 is ALSO SUFFICIENT TO TELL ME THAT THE SET WOULD NOT CONTAIN ALL +VE MULTIPLES OF 3. In this interpretation, Statement (2) is also SUFFICIENT.
But given that "infinity" itself is an ethereal concept, take your pick!
Rehana |
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yogeshsheth Just gettin' started!
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Posted: Sun Sep 03, 2006 5:04 am Post subject: |
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My Pick would be A
As per statement 1 if 3 is there then all postive multiples of 3 will be there so it is sufficient.
As per statement 2 you can definately say that all negative multiples of 3 are present but nothing concrete can be said about positive multiples of 3. So statement 2 is insufficient.
So my pick is A |
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kulksnikhil Rising GMAT Star
Joined: 23 May 2006 Posts: 58
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Location: Seoul, Korea
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Posted: Tue Nov 14, 2006 11:09 pm Post subject: Re: Number Properties |
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| jtsgmat wrote: | Does anyone know how to solve this?
If P is a set of integers and 3 is in P, is evervy positive multipe of 3 in P?
1) For any integer in P, the sum of 3 and that integer is aslo in P.
2) For any integer in P, that integer minus 3 is also in P.
AD
BCE
Jason |
My pick is D, since it is asking for a positive multiple .. I guess, the answer is D.. the set might have numbers like 0, 0+3, 3+3, 6+3, etc...
or 3, 3-3, 6-3, 9-3 etc... |
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gmat_enthus Rising GMAT Star
Joined: 18 Oct 2006 Posts: 62
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Posted: Fri Nov 24, 2006 1:51 pm Post subject: Re: Number Properties |
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| jtsgmat wrote: | Does anyone know how to solve this?
If P is a set of integers and 3 is in P, is evervy positive multipe of 3 in P?
1) For any integer in P, the sum of 3 and that integer is aslo in P.
2) For any integer in P, that integer minus 3 is also in P.
AD
BCE
Jason |
1. Since 3 is given to be in P then 3+3 is also in P, then 3+3+3 is also in P. So all multiples of 3 are in P. sufficient
2. 3 is given to be in P. No other integer inside P is given. all we can say is 3-3 is in P. 3-3-3 is also in P. So negative multiples are there in P. But nothing more known about the set P so cannot definitely say that P doesnt contain all the positive multiples of 3. so insufficient
I think A. What is OA? _________________ My 760 | GMAT Preparation Suggestion
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