Question on Perfect Square 3

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Question on Perfect Square 3

by richachampion » Sun Oct 16, 2016 3:05 am
Is the positive integer x a perfect square?

(1) x = t^n, where t is a positive integer and n is odd.
(2) x^0.5=k, where k is a positive integer.
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by richachampion » Sun Oct 16, 2016 3:06 am
OA: B
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by fiza gupta » Sun Oct 16, 2016 6:28 am
1) x = t^n, where t is a positive integer and n is odd.
let t=4,n=3 x=64;is square root 8
let t=3,n=3 x=27,not a perfect square
NOT SUFFICIENT

2) x^0.5=k, where k is a positive integer.
x=k^2
x is a perfect square root
SUFFICIENT
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by Jay@ManhattanReview » Fri Dec 30, 2016 4:46 am
richachampion wrote:Is the positive integer x a perfect square?

(1) x = t^n, where t is a positive integer and n is odd.
(2) x^0.5=k, where k is a positive integer.
If X is a perfect square, then X^(1/2) = C; where C is a positive integer

S1: Given that X = t^n

If t itself is a perfect square, then X = t^n is a perfect square; for example, t = 1, 4, 9, and n = 1, 3, 5, etc. The answer is YES.
However, if t itself is not a perefct square, then X = t^n is not a perfect square; for example, t = 2, 3, 5, and n = 1, 3, 5, etc. The answer is No.
No unique answer. insufficient.

S2: X^0.5 = K is the requisite condition for a number X to be a perfect square. Sufficient.

OA: B

-Jay
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