if a & B are consteants MGMAT

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if a & B are consteants MGMAT

by rommysingh » Wed Aug 19, 2015 2:31 am
If a and b are constants, what is one solution of the equation (x + a)(x - b) = 0?

(1) a = 4

(2) b = 3

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by Uva@90 » Thu Aug 20, 2015 8:41 am
rommysingh wrote:If a and b are constants, what is one solution of the equation (x + a)(x - b) = 0?

(1) a = 4

(2) b = 3
IS OA E ?

Pls post OA

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Uva
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by Brent@GMATPrepNow » Thu Aug 20, 2015 8:47 am
rommysingh wrote:If a and b are constants, what is one solution of the equation (x + a)(x - b) = 0?

(1) a = 4
(2) b = 3
Target question: What is one solution of the equation (x + a)(x - b) = 0

Statement 1: a = 4
This means the equation is (x + 4)(x - b) = 0
So, x = -4, is one possible solution to the equation.
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: The b = 3
This means the equation is (x + a)(x - 3) = 0
So, x = 3, is one possible solution to the equation.
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = D

Aside: I don't think I've seen an official GMAT question ask for ONE solution to a quadratic equation. Typically, we're either asked for the value of a variable or asked some yes/no question about the value of the variable (e.g., "Is x > 3?). What's the source?

Cheers,
Brent
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by Max@Math Revolution » Fri Aug 21, 2015 8:12 pm
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If a and b are constants, what is one solution of the equation (x + a)(x - b) = 0?

(1) a = 4

(2) b = 3

==> In the original condition, x=-a, and thus we have 2 variables -a,b, meaning we need 2 equations to match the number of variables. Since we have 1 each for both (1), (2) the answer is likely C. Using both (1) & (2) together, x=-4,3 is our solution yet it is not unique, and thus NOT sufficient. Therefore the best answer is E



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