Problem Solving

Hi melanie.espleland,

Functions are really just equations for graphs. Function questions can often be solved by TESTing VALUES or doing algebra.

Here, we're asked which of these functions has the same RESULT when you plug in (X) and (1-X). This is a perfect situation for TESTing VALUES.

Since we're dealing with functions/graphs, we can TEST any value for X that we want. Let's keep things super-easy and use X = 0.

So, we now need to plug in 0 and 1-0 = 1 into each equation and track the results...

Answer A:
X = 0 ===> 1
X = 1 ===> 0
Not the same result

Answer B:
X = 0 ===> 1
X = 1 ===> 0
Not the same result

Answer C:
X = 0 ===> 0 - 1 = -1
X = 1 ===> 1 - 0 = 1
Not the same result

Answer D:
X = 0 ===> 0(1) = 0
X = 1 ===> 1(0) = 0
SAME RESULT

Answer E:
X = 0 ===> 0/1
X = 1 ===> 1/0
Not the same result

Final Answer: D

GMAT assassins aren't born, they're made,
Rich

Hi melanie.espeland,

Here's some information about how to interpret function "language":

If we're given:
f(X) = X + 10

Then you can rewrite the function as:
Y = X + 10
and then graph it.

With this same function, if we have:
f(3) = X + 10
then we have to plug 3 in for "x" to get an end result...
f(3) = 3 + 10 = 13

In this question, we're asked for:
f(X)
f(1-X)
which means that we have to plug in each of those values wherever we see an "x"; the question asks us to find the function that has the SAME end result when you plug in EACH of those values. Given the relative complexity of some of the answer choices, it's easier to TEST Values than to plug in (X) and (1-X) and do all that algebra.

With the example I used (X = 0), so we're looking for:
f(0)
f(1)

Only Answer D gives us the same end result for both.

GMAT assassins aren't born, they're made,
Rich

me_1234 wrote:Can someone please explain this problem to me? Thank you!

For which of the following functions f is f(x) = f(1-x) for all x?

f(x) = 1 - x

f(x) = 1 - x²

f(x) = x² - (1 - x)²

f(x) = x²(1 - x)²

f(x) = x / (1 - x)

Since we are not given any restrictions on the value of x, let's let x = 1. Thus, we are determining for which of the following functions is f(1) = f(1-1), i.e., f(1) = f(0). Next, we can test each answer choice using our value x = 1.

A. f(x) = 1 - x

f(1) = 1 - 1 = 0

f(0) = 1 - 0 = 1

Since 0 does not equal 1, A is not correct.

B. f(x) = 1 - x^2

f(1) = 1 - 1^2 = 1 - 1 = 0

f(0) = 1 - 0^2 = 1 - 0 = 1

Since 0 does not equal 1, B is not correct.

C. f(x) = x^2 - (1 - x)^2

f(1) = 1^2 - (1 - 1)^2 = 1 - 0 = 1

f(0) = 0^2 - (1 - 0)^2 = 0 - 1 = -1

Since 1 does not equal -1, C is not correct.

D. f(x) = x^2*(1 - x)^2

f(1) = 1^2*(1 - 1)^2 = 1(0)= 0

f(0) = 0^2*(1 - 0)^2 = 0(2) = 0

Since 0 equals 0, D is correct.

Alternate Solution:

Let's test each answer choice using x and 1 - x.

A. f(x) = 1 - x

f(x) = 1 - x

f(1 - x) = 1 - (1 - x) = x

Since 1 - x does not equal x, A is not correct.

B. f(x) = 1 - x^2

f(x) = 1 - x^2

f(1 - x) = 1 - (1 - x)^2 = 1 - (1 + x^2 -2x) = 2x - x^2

Since 1 - x^2 does not equal 2x - x^2, B is not correct.

C. f(x) = x^2 - (1 - x)^2

f(x) = x^2 - (1 - x)^2 = x^2 - (1 + x^2 - 2x) = 2x - 1

f(1 - x) = (1 - x)^2 - (1 - (1 - x))^2 = 1 + x^2 - 2x - x^2 = 1 - 2x

Since 2x - 1 does not equal 1 - 2x, C is not correct.

D. f(x) = x^2*(1 - x)^2

f(x) = x^2*(1 - x)^2

f(1 - x) = (1 - x)^2*(1 - (1 - x))^2 = (1 - x)^2*x^2

Since x^2*(1 - x)^2 equals (1 - x)^2*x^2, D is correct.

Answer: D