In the figure shown, two identical squares are inscribed in the rectangle. If the perimeter of the
rectangle is 18*square root 2, then what is the perimeter of each square?
A. 8*square root 2
B. 12
C. 12*square root 2
D. 16
E. 18
OA – B
Two sqares in a rectangle
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Last edited by crackgmat007 on Sat May 09, 2009 9:33 pm, edited 1 time in total.
- DanaJ
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The perimeter of the rectangle will be 2(length + width) = 18*sqrt(2). This means that you get length + width = 9sqrt(2).
Now look at the picture and try to figure out what is length and width of rectangle in terms of x, with x = side of square.
As you can plainly see, the length will be two times the diagonal of the square, while the width will be equal to the diagonal of the square. In terms of x, the diagonal will be x*sqrt(2) (since the diagonal of a square is always equal to side of the square times sqrt(2)).
This means that you get:
length = 2*x*sqrt(2)
width = x*sqrt(2)
--------------------
3*x*sqrt(2) = 9*sqrt(2).
x = 3.
Since the side of a rectangle is 3, then the perimeter will be 4x = 12.
Now look at the picture and try to figure out what is length and width of rectangle in terms of x, with x = side of square.
As you can plainly see, the length will be two times the diagonal of the square, while the width will be equal to the diagonal of the square. In terms of x, the diagonal will be x*sqrt(2) (since the diagonal of a square is always equal to side of the square times sqrt(2)).
This means that you get:
length = 2*x*sqrt(2)
width = x*sqrt(2)
--------------------
3*x*sqrt(2) = 9*sqrt(2).
x = 3.
Since the side of a rectangle is 3, then the perimeter will be 4x = 12.
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I am sorry i failed to understand your explanation.Could you please help me out with a detailed explanation...DanaJ wrote:The perimeter of the rectangle will be 2(length + width) = 18*sqrt(2). This means that you get length + width = 9sqrt(2).
Now look at the picture and try to figure out what is length and width of rectangle in terms of x, with x = side of square.
As you can plainly see, the length will be two times the diagonal of the square, while the width will be equal to the diagonal of the square. In terms of x, the diagonal will be x*sqrt(2) (since the diagonal of a square is always equal to side of the square times sqrt(2)).
This means that you get:
length = 2*x*sqrt(2)
width = x*sqrt(2)
--------------------
3*x*sqrt(2) = 9*sqrt(2).
x = 3.
Since the side of a rectangle is 3, then the perimeter will be 4x = 12.
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I like this kind of explanation.
but why are you multiplying 3/2 * sq rt 2 with sq rt 2????
what is the sq rt 2 in this case ?
- DanaJ
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I think I can't go into more detail that I already have. If you can point out a specific issue you're having with the explanation, I'd be happy to help!bhumika.k.shah wrote: I am sorry i failed to understand your explanation.Could you please help me out with a detailed explanation...
reply by manish8109
i found it really helpfull.....
read carefully pls if u really want to understand question...
If perimeter of rectangle= 18sqrt(2)
=> 2(a+b) = 18sqrt(2)
=> a+b=9sqrt(2) where a= length & b=breadth
Square side=s
Consider 1st square,
Diagonal=s* sqrt(2)=b(Breadth)
Consider 1st & 2nd square
diagonal 1+ diagonal2= 2s*sqrt(2)=a(Length)
=> 3s*sqrt(2)= 9 sqrt(2)
=> 3s=9
=> s=3
permeter of square=4*s=4*3=12 Ans(B)
i found it really helpfull.....
read carefully pls if u really want to understand question...
If perimeter of rectangle= 18sqrt(2)
=> 2(a+b) = 18sqrt(2)
=> a+b=9sqrt(2) where a= length & b=breadth
Square side=s
Consider 1st square,
Diagonal=s* sqrt(2)=b(Breadth)
Consider 1st & 2nd square
diagonal 1+ diagonal2= 2s*sqrt(2)=a(Length)
=> 3s*sqrt(2)= 9 sqrt(2)
=> 3s=9
=> s=3
permeter of square=4*s=4*3=12 Ans(B)
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Here is how I tackled this one.
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