| View previous topic :: View next topic |
| Author |
Message |
isisalaska Moderator
Joined: 10 Dec 2006 Posts: 364
Thanks given: 0 Thanked 0 times in 0 posts
Location: St. Louis
|
Posted: Tue Mar 27, 2007 2:01 pm Post subject: Two more form internet #17, 18, section 14 |
|
|
17- If x<0, is y>0?
10 x/y <0
2) 7-x>0
Why is A? I am thinking what if x=-3 and y=-4, still x/y ,0 BUT y <0
but if x=-3 and y=4 , y>0, I am confused...
_________________________________________
18- If x,y,z are positive integers, is x-y odd?
1) x=Z^2
2) y=(z-1)^2
Answer is C _________________ Isis Alaska |
|
| Back to top |
|
 |
|
|
jayhawk2001 Moderator

Joined: 28 Jan 2007 Posts: 789
Thanks given: 0 Thanked 11 times in 11 posts
Location: Silicon valley, California
|
Posted: Tue Mar 27, 2007 11:00 pm Post subject: Re: Two more form internet #17, 18, section 14 |
|
|
| isisalaska wrote: | 17- If x<0, is y>0?
10 x/y <0
2) 7-x>0
Why is A? I am thinking what if x=-3 and y=-4, still x/y ,0 BUT y <0
but if x=-3 and y=4 , y>0, I am confused...
|
If x=-3 and y=-4, x/y is positive. Basically for x/y to be < 0, either
x < 0 or y < 0 but not both. So, if we know that x < 0, then y has
to be positive.
| isisalaska wrote: |
_________________________________________
18- If x,y,z are positive integers, is x-y odd?
1) x=Z^2
2) y=(z-1)^2
Answer is C |
1 - insufficient. Don't know y
2- insufficient. Don't know x
Combining 1 and 2, z or z-1 has to be even.
If z is even, x is even and y is odd and x-y is always odd
If z is odd, x is odd and y is even and so x-y is again odd
So C |
|
| Back to top |
|
 |
Cybermusings GMAT Destroyer!
Joined: 27 Mar 2007 Posts: 559
Thanks given: 0 Thanked 0 times in 0 posts
|
Posted: Wed Mar 28, 2007 4:17 am Post subject: |
|
|
17- If x<0, is y>0?
10 x/y <0
2) 7-x>0
Substitute values to find the answer. x<0. thus x is negative
Thus for x/y to be less 0 y would have to be positive else the x/y won't be less than 0. hence A itself is sufficient
Take the second statement
7-x > 0
This doesnt tell us anything about the variable y. Hence 2 alone is insufficient.
Thus it is choice A for question 17 |
|
| Back to top |
|
 |
Cybermusings GMAT Destroyer!
Joined: 27 Mar 2007 Posts: 559
Thanks given: 0 Thanked 0 times in 0 posts
|
Posted: Wed Mar 28, 2007 4:28 am Post subject: |
|
|
If x,y,z are positive integers, is x-y odd?
1) x=Z^2
2) y=(z-1)^2
Statement 1 just tells us that x is the square of z. It doesn't mention anything about y. Moreover x can be odd ( example 3^2 = 9 ) or even (4 ^ 2 = . Thus Statement 1 alone is insufficient
Statement 2 says that y is the square of a number 1 less than z. Again z can be even or odd and thus the square of z - 1 can be odd or even respectively. Moreover it doesn't say anything about x which can be even or odd. Hence 2 alone is insufficient
Now combine the 2
Let's take z = 6 (an even number)
x = 6^2 = 36
y = (6-1)^2 = 25
36 - 25 = 11 (odd)
Lets take a case where z is odd (11)
x = 11^2 = 121
y = 10^2 = 100
121 - 100 = 21 (odd)
Hence both statements together are sufficient but neither statement alone will suffice. it's C |
|
| Back to top |
|
 |
|
|
You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot vote in polls in this forum You cannot attach files in this forum You cannot download files in this forum
|
|
"GMAT" and other GMAC™ trademarks are registered trademarks of the Graduate Management Admission Council™. The Graduate Management Admission Council™ does not endorse, nor is it affiliated in any way with the owner or any content on this website. The opinions expressed here are solely those of the author or those of the members of this website. Copyright © 2008 BTG Test Prep, LLC. Powered by phpBB © 2001, 2005 phpBB Group.
|
|